Calculating Z Component of Velocity on Earth's Surface | Tips & Examples

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Homework Help Overview

The discussion revolves around calculating the Z component of velocity for an object on Earth's surface, specifically in the context of rotational motion and coordinate systems. The original poster is attempting to understand how to derive the Z and X components of velocity after a certain time, given an initial tangential velocity.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to relate the Z and X components of velocity using the Pythagorean theorem and considers the effects of Earth's rotation on these components over time. Some participants question the clarity of the coordinate system and suggest defining it more precisely.

Discussion Status

Participants are actively exploring different interpretations of the problem, with one suggesting a method involving the sine function to calculate the Z component. There is no explicit consensus on the correctness of the calculations or the approach being taken.

Contextual Notes

There are indications that the original poster may be assuming a specific coordinate system without fully articulating it, and some participants highlight the need for a more comprehensive framework to describe the velocity components accurately.

Wizardsblade
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Hey, I was trying doing some calculations and ran across a question I just can’t figure out. Hopefully I explain this well.
I am trying to find the Z component of velocity of an object on earth’s surface after a given time. For example a rock lies on the ground with a tangential velocity of ~450m/s (I believe). 1 second later it will be going v1 speed in the negative z direction and v2 speed in the x direction. I believe v1^2+v2^2=450^2 but I really don't know where to go from here.
 
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Define your coordinate system and state the problem a little more carefully. At it stands it is unclear.
 
At time = 0 the z axis is up and down and the x-axis is forward and backward in the direction of Earth's rotation, i.e. looking at the Earth form above the earth. What I am trying to figure out is the x and z components at any give time. For example at time = 6 hours the x component will be 0 and the z component will be -450m/s, at time = 12 hours z=0 and x=-450m/s.
 
Wait I think I figured out a way. I did this: t=1s so I figured the number of seconds in a day (24*60*60=86400) and divided 360 degrees by 86400 and got .0041. Then I took the sin of .0041 and multiplied by 450m/s. So I got 7.2x10^-5m/s. Is this correct for the z component?
 
Unless you're standing at the equator you're going to need three basis vectors in the fixed frame of reference to describe those vectors.

What you are calling z corresponds to the radial coordinate in a spherical coordinate system so that a unit vector in the direction is given by

[tex]\hat r = \sin \theta \cos \phi \hat i + \sin \theta \sin \phi \hat j + \cos \theta \hat k[/tex]

With the simple rotation you've defined simply replace [itex]\phi[/itex] with [itex]\omega t[/itex]. Also, what you are calling the x direction corresponds to a vector in the azimuthal direction ([itex]\phi[/itex]) and the corresponding unit vector is given by

[tex]\hat \phi = -\sin \phi \hat i + \cos \phi \hat j[/tex]
 

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