Calculations for Hydraulic Jacks lifting a load

[doconnor17dan]

Homework Statement

can somone check my working out ?

Relevant Equations

p=f/a

This cylinder is connected by a pipe to the larger diameter jack cylinder on the right where pressure p2 acts on the piston which has an area A2 and is able to lift a load equivalent to the force F2. The piston area of the hand pump cylinder is 2.0 cm2, the piston area of the jack piston is 10.0 cm2 and the force being applied F1 = 98.1 N

Here is my working out , would like to see If its correct ?

1. Which of the following is correct? 2. F1 > F2 3. F1 = F2 4. F1 < F2

2. Calculate the load being lifted by the jack cylinder in Kg's Pressure P1=P2 Force F1 = 98.1N P1=F1/A1 =98.1N / 2.0cm^2 = 4.905 N/cm^2 P2= P1 thus P2=4.905 N/cm^2 Thus P2=F2/A2 Thus F2 = P2XA2= 4.905x10 = 49.05N = approx. 49.05/0.102 = 5kg

 

[hmmm27]

Not to be more pedantic than usual but... the "Homework Statement" is where you put the exercise text, not the begging for help bit.

Ditto, to the other guy who did the same thing a minute ago.

And, right underneath the reply box is "LaTeX Guide", which - if used - can help people read what you've written.

And, your diagram's sideways.

And, something else, can't remember, oh yeah more bitching about the equations : lack of dimensions, lack of checking your work to see if it makes sense, etc.

Protip : the "Enter" key, on the right hand side of the keyboard, can be used to insert what's called a "line break".

As far as the answer is concerned, you can either do it in your head - not complex - or write it out nice and neat and people will check it for you and make rude comments when they have difficulty reading it.

Just sayin'. Carry on.

 

[haruspex]

98.1N / 2.0cm^2 = 4.905 N/cm^2

?