Calculus II - Series Comparison Test Problems

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SUMMARY

The discussion focuses on the convergence of two series using the comparison tests in calculus. The first series, Σ (ln n)^3 / n^2, can be compared to the convergent p-series 1/n^2, while the second series, Σ (1 / sqrt(n) * (ln n)^4), requires a different approach due to its divergence characteristics. The participant seeks guidance on selecting appropriate comparison terms (bn) for both series to effectively apply the direct and limit comparison tests.

PREREQUISITES
  • Understanding of series convergence and divergence
  • Familiarity with the Direct Comparison Test
  • Knowledge of the Limit Comparison Test
  • Basic properties of logarithmic functions
NEXT STEPS
  • Research the properties of p-series and their convergence criteria
  • Study examples of the Direct Comparison Test in detail
  • Explore the Limit Comparison Test with various functions
  • Investigate the growth rates of logarithmic functions compared to polynomial functions
USEFUL FOR

Students studying calculus, particularly those focusing on series convergence, as well as educators seeking to enhance their teaching methods for comparison tests in series analysis.

invasmani
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Homework Statement



I have two relatively similar problems:

1.) Sigma n=1 to infinity ((ln n)^3 / n^2)
2.) Sigma n=1 to infinity (1 / sqrt(n) * (ln n)^4)

I'm to prove their convergence or divergence using either the direct comparison test or the limit comparison test.

I understand both comparison tests, however, I am very much stumped on how to determine a working bn for the problems.

The Attempt at a Solution



I've tried using a known p-series, such as 1/(n^2) for problem #1, which is convergent. However, that p-series is not greater than the an in this case.

I'd appreciate any sort of direction on this.
 
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ln(n) grows more slowly than any power x^p for p>0. Can you suggest an interesting value of p that's relevant for 1) or 2)?
 
Last edited:

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