Calculus of Variations - Fermat's Principle

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SUMMARY

The discussion focuses on Fermat's principle in the context of the calculus of variations, specifically addressing the time taken for light to travel through a medium where the speed of light, c(x,y), varies with position. The participants derive the time functional T = INT[x1,x2] Sqrt(1+y'^2)/c(x,y) dx and explore the Euler-Lagrange equation, particularly its special case when c is independent of x. They also analyze the implications of substituting c = 1+y to demonstrate that light emitted from the origin at an angle t travels in a circular path centered at (tan(t), -1).

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  • Understanding of calculus of variations
  • Familiarity with Fermat's principle
  • Knowledge of Euler-Lagrange equations
  • Basic concepts of differential equations
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  • Study the derivation of the Euler-Lagrange equation in detail
  • Explore applications of Fermat's principle in optics
  • Investigate the implications of variable speed of light in different media
  • Learn about the geometric interpretation of light paths in calculus of variations
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SunGod87
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Light travels in a medium in which the speed of light c(x,y) is a function of position. Fermat's principle states that the time required for light to travel between two points is an extremum relative to all possible paths connecting the two points.

1) Show that the time for the light to travel from point (x1,y1) to (x2,y2) along the path y(x) is
T = INT[x1,x2] Sqrt(1+y'^2)/c(x,y) dx - Completed

2) Write down the Euler-Langrange equation for this functional
b) and its special form for when c is independent of x.

2a:
(1+y'^2)^(1/2) d(1/c)/dy - d/dx[y'/(c (1+y'^2)^(1/2))] = 0
Is as far as I can get, how should I continue this? Perhaps by noting d(1/c)/dy = (-dc/dy)/c^2 ?

2b:
(1 + y'^2)^(1/2)/c - y' (y'/c(1+y'^2)^(1/2)) = constant (A)
(1 + y'^2 - y'^2)/c(1+y'^2)^(1/2)) = A
1/c(1+y'^2)^(1/2)) = A
c(1+y'^2)^(1/2) = B = 1/A
c^2 (1+y'^2) = D = B^2 = 1/A^2; is this correct?

2c: If light is emitted from the origin making an angle t (0 <= t <= pi/2) with the positive x-axis in a medium in which c(x,y) = 1+y, show that the light travels in a circle centre (x,y) = (tan(t), -1)

Presumably for this I need to make the substitution c = 1+y into the equation derived in 2b (since there will be no dependence on x) and work from there to obtain the equation of a circle?
 
Last edited:
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I actually have this exact same problem and I'm stuck in exactly the same places.
 

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