Calculus of Variations with Inequality Constraints

Click For Summary
SUMMARY

The discussion centers on the calculus of variations with inequality constraints, specifically addressing the constraint function of the form f(x)x - ∫_{x_0}^x f(z) dz ≤ K. The participant, MDR123, seeks clarification on handling constraints that depend on both x and integral conditions. A suggestion is made to utilize the fundamental theorem of calculus to reformulate the condition as f(x)x - F(x) = ∫_{x_0}^x f'(z)z dz ≤ K_1, which may provide a clearer approach to the problem.

PREREQUISITES
  • Understanding of calculus of variations
  • Familiarity with inequality constraints in optimization
  • Knowledge of the fundamental theorem of calculus
  • Basic concepts of integral calculus
NEXT STEPS
  • Research the application of the fundamental theorem of calculus in optimization problems
  • Explore techniques for handling inequality constraints in calculus of variations
  • Study examples of constraint functions in variational problems
  • Investigate bounded range implications on optimization solutions
USEFUL FOR

Mathematicians, optimization researchers, and students studying calculus of variations who are dealing with inequality constraints in their work.

MDR123
Messages
2
Reaction score
0
Hi, I am working on a calculus of variations problem and have a general question.

Specifically, I was wondering about what kind of constraint functions are possible.

I have a constraint of the form:

f(x)x - \int_{x_0}^x f(z) dz \leq K

If I had a constraint that just depends on x or a pure integral condition how to deal with it. However, it is unclear to me how to deal with a condition that depends upon both.

My other idea for an approach is to notice that the above condition is increasing if f is increasing. In addition, I have a bounded range for x. So, I know the below condition implies the above condition, but how to apply it to a calculus of variations question is unknown to me as well.

f(\bar{x})\bar{x} - \int_{x_0}^{\bar{x}} f(z) dz \leq K
f'(x) \geq 0

Thank you,
MDR123
 
Physics news on Phys.org
You could use the fundamental theorem of calculus and write your condition as ##f(x)x-F(x) = \int_{x_0}^x f'(z)z\,dz\leq K_1##. Maybe this helps.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 22 ·
Replies
22
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K