Calculus Problem: Blowing Up a Spherical Balloon

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Homework Help Overview

The discussion revolves around a calculus problem involving the dynamics of a spherical balloon, specifically focusing on the relationship between the radius and volume as the balloon inflates over time.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are examining the assumption that the rate of change of the radius (dr/dt) is constant, questioning its validity based on the information provided in the problem. There is also discussion about the implications of a constant volume flow rate and how it relates to the variable nature of dr/dt.

Discussion Status

The conversation is actively exploring different interpretations of the problem, with some participants suggesting calculations that could clarify the relationships between the variables involved. Guidance has been offered regarding the need to calculate the derivative of volume with respect to radius to further inform the discussion.

Contextual Notes

Participants are navigating the constraints of the problem, particularly the specific conditions under which dr/dt is defined and the implications of a constant volume flow rate. There is an acknowledgment of the need for careful consideration of the assumptions made in the calculations.

Idan9988
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Homework Statement
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Relevant Equations
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IMG_20230527_195520.jpg

I'm struggling with section a. This is my calculation:
IMG20230527195328.jpg

The expression remains depend on the variable t, while in the answer is a concrete number:
Screenshot_2023-05-27-19-54-03-99_e2d5b3f32b79de1d45acd1fad96fbb0f.jpg
 
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r = r_0 + 0.9t is only valid if dr/dt is constant.

Why did you assume that dr/dt was constant? The question only tells you that dr/dt = 0.900\,\mathrm{cm}/\mathrm{s} when r = 6.50\,\mathrm{cm}.
 
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Likes   Reactions: Idan9988, malawi_glenn and erobz
Agree,

The answer (a) has all the information. Since the volume flow rate is constant, then ##\frac {dV}{dt}## is a constant.

##\frac {dr}{dt}## is variable.

If you rearrange the expression to solve for ##\frac {dr}{dt}## and you get the answer to (b) and the behavior that explains (c).
 
Calculate ##\frac {dV} {dr}## and use this to inform your answer.
 

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