The series from n = 1 infinity of 1/(n*(3^n)) must(adsbygoogle = window.adsbygoogle || []).push({});

A) converge to a value greater than 1/4

B) converge to a value greater than 1/9

C) Converge to a value less than 1/8

D) converge to a value less than 1/2

E) diverge.

I know the series definitely does not diverge because the series (1/3)^n is a geometric series which converges and the series is question is smaller than that geometric series so it much converge by the direct comparision test.

But I am not sure how to see what it would converge to. Can someone help?

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# Homework Help: Calculus question involving an infinite series

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