I took the Calculus AB AP test, and there were a total of 6 open-ended problems. Most of them I knew exactly how to do, but there was one in particular that gave me some real problems. We haven't done much on function composition, so maybe that's why I couldn't do it (but I have the feeling that I'm just overlooking something). This table is given: Code (Text): x f(x) f'(x) g(x) g'(x) 1 6 4 2 5 2 9 2 3 1 3 10 -4 4 2 4 -1 3 6 7 The functions f and g are differentiable for all real numbers, and g is strictly increasing. The table above gives the values of the functions and their first derivatives at selected values of x. The function h is given by h(x) = f(g(x)) - 6. a) Explain why there must be a value r for 1 < r < 3 such that h(r) = -5 b) Explain why there must be a value c for 1 < c < 3 such that h'(c) = -5 c) Let w be the function given by w(x) = integral of f(t)dt from 1 to g(x). Find the value of w'(3). d) If g^-1 is the inverse function of g, write an equation for the line tangent to the graph of y = g^-1(x) at x=2 So far, all I've established is that f and g are continuous, g'(x) will always be positive, and g(x) will always be less than g(x+1). Everything I know is just the obvious, I don't know where to go next! Can someone please give me the solution so I can quit worrying about this stupid problem? Thanks for any help!