Calorimetry Problem: Calculate Final Temp.

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SUMMARY

The discussion focuses on calculating the final temperature of a solution after dissolving 25.00g of silver nitrate (AgNO3) in 250.0mL of water at an initial temperature of 21.75°C, using a copper calorimeter weighing 750.0g. The enthalpy change (ΔH) for the dissolution is given as 0.908 kJ. Participants emphasize the need to calculate the heat absorbed by both the solution and the calorimeter, applying the specific heat capacity of copper (c(Cu) = 0.3900 J/g°C) and the heat capacity of water.

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  • Understanding of thermochemistry and enthalpy changes
  • Knowledge of specific heat capacity calculations
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  • Calculate the heat released during the dissolution of AgNO3 using ΔH.
  • Learn how to apply the formula Q = mcΔT for both the solution and the calorimeter.
  • Explore the concept of heat transfer in calorimetry experiments.
  • Study the relationship between moles of solute and temperature change in solutions.
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Acidburn
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I have a question that i cannot get an answer too.

AgNO3 (s) ---> Ag (aq) + NO3 (aq)

THESE ARE THE GIVEN:
ΔH=0.908 kJ
c(Cu)=0.3900 J/g ͦC
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Calculate the final temperature of a solution if 25.00g of pure AgNO3 is dissolved in 250.0mL of water (initially at 21.75 ͦC) in a 750.0g copper calorimeter.

Answers are appreciated. Thanks!
 
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You are to assume that the solution water heat capacity is that of pure water. Other than that you have one source of heat and heat is absorbed by both copper calorimeter and solution.

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methods
 
yeah thermochem was always hell. i think you need to find the amount of heat from the reaction. is that enthalpy value J/mol? well, you know how many moles are reacting (simple conversion). you also know the mass of the final solution and as was stated in the previous post, you have heat capacity values.
 

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