Can a group have monomorphisms in both directions and still not be isomorphic?

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Discussion Overview

The discussion revolves around the question of whether two groups can have monomorphisms in both directions and still not be isomorphic. Participants explore this concept in the context of group theory, particularly focusing on finite and infinite groups.

Discussion Character

  • Debate/contested
  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant questions if monomorphisms from group A to group B and from group B to group A imply that A and B are isomorphic.
  • Another participant suggests that for finite groups, such injections imply a bijection due to equal size, but expresses uncertainty regarding infinite groups.
  • A participant later concludes that the statement is not generally true.
  • One participant proposes a counterexample involving free (non-abelian) groups on different sets of generators, specifically referencing the fundamental group of a figure eight knot and its covering space.
  • Further elaboration includes the idea that the free group on two generators can inject into a free group on an infinite countable number of generators, while remaining non-isomorphic.

Areas of Agreement / Disagreement

Participants do not reach a consensus; there are competing views regarding the implications of monomorphisms in both directions, particularly between finite and infinite groups.

Contextual Notes

Participants express uncertainty about the general case for infinite groups and the limitations of their examples. The discussion includes references to specific mathematical concepts and literature, indicating a reliance on definitions and theorems that may not be universally agreed upon.

Who May Find This Useful

This discussion may be of interest to those studying group theory, particularly in understanding the implications of monomorphisms and exploring examples of non-isomorphic groups.

charlamov
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Is it true that if there is monomorphism from group A to group B and monomorphism from group B to group A than A and B are isomorphic? i need some explanation. thx
 
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Yes, I think that is true. At least for finite groups, because an injection both ways implies they have the same size, which means it is a bijection. Not sure about infinite groups, a good strategy for trying to find if something is true or not, is try proving either and see what facts you lack, try to construct a counterexample, which may help continue trying to prove truth, back and forth till you realize if it's true or not.

So if you can't see a proof for the infinite case as I haven't, try constructing a counterexample.
 
thanks, i finally have found that it is not true generally
 
did you find the counterexample?
 
i guess the usual example is of free (non abelian) groups on different sets of generators.

as i recall, a figure eight knot has a fundamental group which is free on two generators. Then you construct a covering space which is a wedge of more than two loops.

The covering space has fundamental group free on more generators, but injects into the fundamental group of the base.

Just recalling a lecture by Eilenberg from 30-40 years ago. I'll check it out.

here's a reference in hatcher's free algebraic topology book, pages 57-61.

http://www.math.cornell.edu/~hatcher/AT/ATpage.html
 
Last edited:
mathwonk said:
i guess the usual example is of free (non abelian) groups on different sets of generators.

as i recall, a figure eight knot has a fundamental group which is free on two generators. Then you construct a covering space which is a wedge of more than two loops.

The covering space has fundamental group free on more generators, but injects into the fundamental group of the base.

Just recalling a lecture by Eilenberg from 30-40 years ago. I'll check it out.

here's a reference in hatcher's free algebraic topology book, pages 57-61.

http://www.math.cornell.edu/~hatcher/AT/ATpage.html



Ah, the above reminded me: the free group [itex]\,F_2\,[/itex] on two generators contains as a subgroup the free group on any number of generators up to and including the free group on infinite countable generators (for example, the group's commutator subgroup [itex]\,(F_2)'=[F_2:F_2]\cong F_\infty\,[/itex]) , so we have injections [tex]F_2\to F_\infty\,\,,\,\,F_\infty\to F_2[/tex] but the two groups are clearly non-isomorphic.

DonAntonio
 

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