Is G/G isomorphic to the trivial group? A proof for G/G\cong \{e\}

However, your summary is missing some key information. Here is a more complete summary:In summary, to prove that G/G\cong \{e\}, where \{e\} is the trivial group, we must show that there is a group isomorphism between G/G and \{e\}. This can be done by first establishing that G is the unique left coset of G in G. From this, we can conclude that G/G=\{G\} and since G\lhd G, the quotient group has order |G/G|=1. Then, we define \phi:G/G\to \{e\} as \phi(G)=e, which is a trivially a group isomorphism
  • #1
lemonthree
51
0
Reorder the statements below to give a proof for \(\displaystyle G/G\cong \{e\}\), where \(\displaystyle \{e\}\) is the trivial group.

The 3 sentences are:
For the subgroup G of G, G is the unique left coset of G in G.
Therefore we have \(\displaystyle G/G=\{G\}\) and, since \(\displaystyle G\lhd G\), the quotient group has order |G/G|=1.
Let \(\displaystyle \phi:G/G\to \{e\}\) be defined as \(\displaystyle \phi(G)=e\). This is trivially a group isomorphism and so \(\displaystyle G/G\cong \{e\}\).

I have ordered the statements to what I believe is right but I would just like to check and ensure I'm thinking on the right track.
Firstly, the question wants a proof for a group isomorphism. So we state that the subgroup of G of G is the unique left coset.
Then G/G has got to be {G} since it's the same group G anyway. We know that the order is 1.
Therefore, we define phi to be the proof, and from there we can conclude the group isomorphism.
 
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  • #2
Yes, the order of the statements is logically correct.
 

1. What is the definition of an isomorphic group?

An isomorphic group is a group that has the same structure as another group, meaning that the elements and the operation between them are preserved.

2. What is the trivial group?

The trivial group, denoted as {e}, is a group that only contains the identity element and has no other elements. It is the simplest and smallest group.

3. Why is G/G isomorphic to the trivial group?

Since G/G is the quotient group of G by itself, it contains only the identity element. This means that the structure of G/G is the same as the structure of the trivial group, making them isomorphic.

4. Can you provide a proof for G/G\cong \{e\}?

Proof: Let G be a group and e be the identity element of G. Then, G/G is the set of all left cosets of G with respect to G. Since G is a group, it contains the identity element e. Therefore, every left coset of G is equal to G. This means that G/G only contains the coset G, which is equivalent to the identity element e. Thus, G/G is isomorphic to the trivial group {e}.

5. Are there any exceptions to G/G\cong \{e\}?

No, there are no exceptions to this statement. For any group G, G/G will always be isomorphic to the trivial group {e}.

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