Can a Rotating Sphere at Relativistic Speeds Create a 'Black Spot'?

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The discussion centers on the relativistic effects of a rotating sphere, particularly a neutron star, and whether it creates a 'black spot' due to length contraction. Participants explore the implications of Lorentz contraction and Terrell rotation, concluding that while the fastest-moving parts of the sphere experience greater contraction, the overall symmetry ensures continuity without gaps. The sphere's appearance is debated, with suggestions that it may appear prolate, yet it is established that the sphere maintains its spherical outline to observers, as supported by R. Penrose's findings.

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  • Understanding of Lorentz contraction in special relativity
  • Familiarity with Terrell rotation and its optical effects
  • Knowledge of neutron stars and their relativistic properties
  • Basic concepts of frame of reference in physics
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  • #31
Looking at this the last section of this video again http://www.youtube.com/watch?v=JQnHTKZBTI4&feature=related it seems to me that the assymetrical visual compression and stretching of the star background in the video is the wrong way around. I think the visual stretching of the stars background should be happening on the left and and visual compression should be happening on the right. I might be wrong as this coclusion is only based on informal ray tracing analysis. Any second opinions on what the inside of a rotating shell would look like from the inside by a stationary observer near (but not exactly at the centre) looking towards the centre?
 
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  • #32
starthaus said:
You need to find all the rays of equal transit time in order to determine the image of the object. In order to do that you need both full-fledged Lorentz transforms, applying length contraction only doesn't solve the problem. your local library will get you the paper for about 1$.

Hi
Unfortunately I am in S E Asia and I doubt that a local library [not that there are any]
can help.
I have found several articles on the web but none containg the the basic parameters of the derivation.

Could you possibly tell me how time dilation and/or simultaneity would apply.

Nutshell answer would be fine.

Thanks
 
  • #33
Austin0 said:
Hi
Unfortunately I am in S E Asia and I doubt that a local library [not that there are any]
can help.
I have found several articles on the web but none containg the the basic parameters of the derivation.

Could you possibly tell me how time dilation and/or simultaneity would apply.

Nutshell answer would be fine.

Thanks

Here is an excellent website that gives you all the mathematical details.
 
  • #34
Austin0 said:
Hi
Unfortunately I am in S E Asia and I doubt that a local library [not that there are any]
can help.
I have found several articles on the web but none containg the the basic parameters of the derivation.

Could you possibly tell me how time dilation and/or simultaneity would apply.

Nutshell answer would be fine.

Thanks

Hi Austin,

I assume you came across this link in your search:

http://math.ucr.edu/home/baez/physics/Relativity/SR/penrose.html

These two links, might be helpful but unfortunately they imply the common misconception that any object (Not just a sphere) can not have its length contraction photographed:

http://arxiv.org/PS_cache/arxiv/pdf/0901/0901.0309v1.pdf
http://www.math.ubc.ca/~cass/courses/m309-01a/cook/terrell1.html

This final link goes into more detail about the visual appearance of moving objects in general and contains some of the maths pertaining to the Lorentz transforms:

http://cdsweb.cern.ch/record/913692/files/0512054.pdf

Unfortunately, none of the freely available documents present the information with much clarity. I am tempted to produce something myself.
 
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  • #35
kev said:
Hi Austin,

I assume you came across this link in your search:

http://math.ucr.edu/home/baez/physics/Relativity/SR/penrose.html

These two links, might be helpful but unfortunately they imply the common misconception that any object (Not just a sphere) can not have its length contraction photographed:

not http://arxiv.org/PS_cache/arxiv/pdf/0901/0901.0309v1.pdf
not http://www.math.ubc.ca/~cass/courses/m309-01a/cook/terrell1.html

This final link goes into more detail about the visual appearance of moving objects in general and contains some of the maths pertaining to the Lorentz transforms:

http://cdsweb.cern.ch/record/913692/files/0512054.pdf

Unfortunately, none of the freely available documents present the information with much clarity. I am tempted to produce something myself.

Thanks kev the last one was informative. It looks like contraction is the only relevant Lorentz effect.
 
  • #36
Austin0 said:
... the last one was informative. It looks like contraction is the only relevant Lorentz effect.

I agree.
 
  • #37
Austin0 said:
Thanks kev the last one was informative. It looks like contraction is the only relevant Lorentz effect.

False, you need the complete set of Lorentz transforms, length contraction alone is not sufficient for explaining the effect. You can buy the Penrose paper here
 
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  • #38
starthaus said:
False, you need the complete set of Lorentz transforms, length contraction alone is not sufficient for explaining the effect. You can buy the Penrose paper here

Thanks for the link but I can't really take advantage of it as I can't luxuries right now.

Once again ,you seem to be very familiar with the original paper so could you just quickly say what effects and where they are applied. No detailed explanations needed.
25 words or less
 
  • #39
starthaus said:
Here is an excellent website that gives you all the mathematical details.

PS I checked out this site ALthough fasc8inating as I have gotten heavily into computer 3-d animation in the past it didnt seem to have any relevant math regarding the original derivation. It was all for writing functions and scripts for a 3-d program.

Thanks
 
  • #40
Austin0 said:
It looks like contraction is the only relevant Lorentz effect.

Yes. As far as I can tell, we only require the length contraction transformation of Special Relativity, to work out that an object that is physically a sphere in its rest frame S, is physicaly an oblate spheriod in frame S' when it has relative inertial motion. After that, all that is required is standard ray-tracing, taking into account the velocity of the oblate spheriod in S' and the finite speed of light, to work out that it can visually appear to be a sphere to observers at frame S'.

We can also note that this apparent visual unobservability of the length contraction of a sphere is only aproximately true, very close to the object and at greater distances from the sphere, the length contraction is increasingly visually observable. For non-spherical objects, the apparent inability to visually observe the length contraction is even less true. It is odd that the very special case of the inability to visually observe the length contraction of one specific shape of object at very limited distances, has led to the popular misconception / myth that length contraction of any object at any distance, is not visually observable.
 
  • #41
kev said:
Yes. As far as I can tell, we only require the length contraction transformation of Special Relativity,

There is no such thing as "the length contraction transformation of Special Relativity".
The Lorentz transforms are space and time transforms and you need both of them to solve this problem:

x'=\gamma(x-vt)
t'=\gamma(t-\frac{vx}{c^2})
y'=y
z'=z to work out that an object that is physically a sphere in its rest frame S, is physicaly an oblate spheriod in frame S' when it has relative inertial motion.[/quote]

You need to find all points at t'=k in S' (line of simultaneity in S'). In order to do that you will need the second Lorentz transform:

k=\gamma(t-\frac{vx}{c^2})

The above, solved for t:

t=k/\gamma+vx/c^2

Substitute t into the expression for x' :

x'=x/\gamma-vk

or:

x=\gamma(x'+vk)

Subsitute the above into the equation of sphere in S:

R^2=x^2+y^2+z^2

R^2=\gamma^2(x'+vk)^2+y'^2+z'^2

meaning that the object is an ellipsoid in S'. The cross-section of the ellipsoid for a viewer situated on the common x-axis is a circular disc. Indeed

x'=a means:y'^2+z'^2=R^2-\gamma^2(a+vk)^2

Note that :

y'^2+z'^2<R^2

For observers not situated along the common x axis, the situaton is more complicated, there is no obvious proof that such an observer obtains a circular disc as the photograph of the ellipsoid.

After that, all that is required is standard ray-tracing, taking into account the velocity of the oblate spheriod in S' and the finite speed of light, to work out that it can visually appear to be a sphere to observers at frame S'.

Can you prove the above? Mathematically, I mean.

We can also note that this apparent visual unobservability of the length contraction of a sphere is only aproximately true, very close to the object and at greater distances from the sphere, the length contraction is increasingly visually observable.

It is still unobservable if the sphere is not textured. Only if the sphere is textured, it is observable.

For non-spherical objects, the apparent inability to visually observe the length contraction is even less true.

Yet, no experimental proof exists (to date). No one has managed to photograph length contraction.
It is odd that the very special case of the inability to visually observe the length contraction of one specific shape of object at very limited distances, has led to the popular misconception / myth that length contraction of any object at any distance, is not visually observable.

There is no such "myth" amongst people who know physics.
 
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