Can a substitution solve this integral problem with Emag integration?

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Homework Help Overview

The discussion revolves around an integral problem related to electromagnetism, specifically the integral of the function 1/[(x²+z²)^(3/2)] with respect to x. Participants are exploring the relationship between their attempts and the solution provided in the textbook.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the validity of the textbook's answer by suggesting checking the partial derivative of the solution. There are attempts to understand the reasoning behind the integral's solution and the original poster's confusion regarding their own approach.

Discussion Status

The conversation is ongoing, with some participants suggesting methods to verify the correctness of the solution. There is an acknowledgment of differing interpretations of the problem, and the original poster expresses a desire for clarity on why their approach differs from the textbook answer.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the extent of guidance provided. There is a focus on understanding the integral's properties rather than arriving at a final solution.

Bigfoots mum
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Now then, I am close to shedding a tear with this one.

This integral has been popping up in a few electromag examples iv been doing and i have absolutely no idea what's going on here.

The integral is 1/[(x2+z2)3/2] with respect to x

According to the textbook the answer is x/[z2(x2+z2)1/2]

I initially, without evening really thinking, went straight for -1/(x[x2+z2]1/2)

Any ideas?
Thanks
 
Last edited:
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First of all, try to find the partial derivative with respect to x (treating z as a constant parameter) of the textbook's answer. If it gives your integrand, then it is correct. If not, it is wrong.
 
Iv used a computer, and it tells me its correct! Otherwise, yes i would have done as you said.
 
So, I guess this issue is resolved.
 
No its not, my question is why is this integral equal to the quoted answer. I gave my attempt at the answer, which is nothing like the actual answer. I am baffled.
 
Oh, so you want to calculate the integral.

Try the substitution [itex]x = z \, \tan(p)[/itex].
 

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