MHB Can a vector space also be a set?

ognik
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Wiki says "A vector space is a collection of objects called vectors, which may be added together and multiplied ("scaled") by numbers, called scalars in this context." To me the term (linear) Vector Space has always seemed a little mysterious ... how far wrong would I be in thinking of a vector space as a set? For example if it was the vector space of polynomials of degree 2, could I also say the set of polynomials of degree 2 (or lower of course)?

If not, what is superior about a Vector Space as opposed to a set?
 
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A vector space is a set, combined with an algebraic structure. A mere set does not satisfy a vector space properties. Whenever a set has certain operations defined on it and behave in a certain way, it is called a vector space. :)
 
Thanks Fantini. So if I have a set of vectors and I say they can be linearly combined, then I have a linear vector space?

I suppose there are mathematical spaces that have other than vectors? And other than linear algebra associated?
 
ognik said:
Thanks Fantini. So if I have a set of vectors and I say they can be linearly combined, then I have a linear vector space?

I suppose there are mathematical spaces that have other than vectors? And other than linear algebra associated?
If you have a set and they can be linearly combined, then they are vectors because they live in a set that is a linear vector space. :) You can only call them vectors if you have a vector space.

There are other mathematical structures different from vector space. You can have a group, a monoid, a module, a ring, a field...there are ample possibilities (though I don't know enough to explain them in detail).
 
Thread 'How to define vector field?'
Hello! In one book I saw that function ##V## of 3 variables ##V_x, V_y, V_z## (vector field in 3D) can be decomposed in a Taylor series without higher-order terms (partial derivative of second power and higher) at point ##(0,0,0)## such way: I think so: higher-order terms can be neglected because partial derivative of second power and higher are equal to 0. Is this true? And how to define vector field correctly for this case? (In the book I found nothing and my attempt was wrong...

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