Can Any 2-Plane Be Mapped to Another Using Linear Maps and Translation?

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Discussion Overview

The discussion explores whether any 2-plane represented by the equation ax+by+cz=d can be mapped to another 2-plane a'x+b'y+c'z=d' using linear maps and translations. The focus includes theoretical approaches to transforming planes in three-dimensional space.

Discussion Character

  • Exploratory
  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant suggests that to map the planes, one could first translate both planes to the origin and then apply rotations based on angles with the axes.
  • Another participant proposes translating each plane to the origin and then using a linear map to relate the basis vectors of each plane.
  • A question is raised about how to find a basis for a plane given only its equation, leading to a proposed basis using specific vector forms when a is nonzero.
  • A follow-up reiterates the need for a basis and suggests a similar approach if a is zero, indicating a method to derive basis vectors based on the coefficients of the plane equation.

Areas of Agreement / Disagreement

Participants express different methods for mapping planes and raise questions about the foundational aspects of defining bases for the planes, indicating that multiple approaches and uncertainties remain in the discussion.

Contextual Notes

There are limitations regarding the assumptions made about the coefficients of the plane equations and the conditions under which the proposed methods are valid. The discussion does not resolve how to handle cases where coefficients are zero.

WWGD
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Hi, just curious as to whether we can map any 2-planep: ax+by+cz=d into any other

2-plane p': a'x+b'y+c'z=d' by using a linear map (plus a translation , maybe). I was thinking

that we could maybe first translate to the origin , for each plane, then , given the

angles ( t,r,s) with the respective x,y,z axes, we could rotate by (-t,-r,-s) to have

a plane z=constant , and do the same for c'. Would that work?
 
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First translate each plane to the origin. Then take a basis for each plane and take a linear map which maps the basis vectors to each other.
 
But how do you find a basis for a plane using only the equation ax+by+cz=0?
 
WWGD said:
But how do you find a basis for a plane using only the equation ax+by+cz=0?

Well

[tex](-b/a,1,0),(-c/a,0,1)[/tex]

is a basis (if a is nonzero). If a is zero, then you must do something analogously with b and c.
 

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