Can anyone help with integrating 4x√(2x+4) dx using integration by parts?

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The discussion focuses on integrating the function 4x√(2x+4) dx using the method of integration by parts. The integration by parts formula is provided, which states that ∫fg dx = f∫g dx - ∫(f'∫g dx) dx. Participants emphasize the importance of showing prior efforts when seeking assistance, particularly in homework contexts.

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I having problem to solve the integration. Can any kindly enough to solve or guide me. thank a lot

4xSquare root 2x+4 dx
 
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HINT: Intergration by parts with two functions f and g

[tex]\int fg \; dx \; = f \int g \;dx \; - \int \left( f' \int g \; dx \right) \; dx[/tex]

For future reference the is a homework section dedicated to homework questions. One is also expected to show ones efforts before requesting help.
 

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