Can anyone provide a proof for

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The discussion centers on the inability to define the product of two distributions in general terms, despite the convergence of sequences of functions to distributions. Specifically, the sequences f_{n}(x) and g_{n}(x) can converge to the Dirac distribution, yet their product may converge to zero or other non-unique results. The conversation highlights the special cases where products can be defined, such as the delta distribution, but emphasizes that these definitions are not universally applicable.

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Can anyone give a proof of why the product of 2 distributions can't be defined ?? :Confused:

In fact i believe (at least it should be) that if f_{n} (x) and g_{n} (x) are a succesion of function for n \rightarrow \infty then the product of the 2 sucessions should be equal to the product of the 2 distributions..

hence f_{n} (x) \rightarrow d(x) and g_{n} (x) \rightarrow e(x) where d(x) and e(x) are 2 distributions then :

f_{n} (x) g_{n} (x) \rightarrow d(x)e(x) ?

I have read about 'MOllifiers' and several methods for generalizing the distribution theory to include product of distributions, also couldn't the product be always defined as a 'sum' (in fact the sum of 2 distributions is defined) since:

a X b = a+a+a+a+a+a+a+a+... (the sum has 'b' terms)

or log(a X b )=log(a) +log(b) :Grumpy:
 
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tpm said:
Can anyone give a proof of why the product of 2 distributions can't be defined ?? :Confused:

It can be defined, but only in certain special cases and in a very special way.

Take the delta distribution defined by \delta[f]:=f(0), where f is in Schwartz Space/ a test function. How would you define \delta^2?
 
you can define \delta (x) \delta (x) = \delta ^{2} (x) in the form.

\delta ^{2} (x) \sim \frac{ sin ^{2} (Nx)}{\pi ^{2} x^{2}}

as N-->oo (N big) , do i get the 'Field medal' for it ?? :Bigrin:
 
tpm said:
or log(a X b )=log(a) +log(b) :Grumpy:

let log(a )=c', and log( b )=c", let's say that both logs have a base "d"( i do not know how to write it )

then by definition we have from the first

d^c'=a, and d^c"=b

if we multiply side by side we get

ab=(d^c')(d^c")=d^(c'+c") so agani by definition we have
log_d(ab)=c'+c", , i guess you can see the rest?
 
Last edited:
tpm said:
f_{n} (x) g_{n} (x) \rightarrow d(x)e(x) ?

This doesn't work. Say that two sequences f_n(x) and g_n(x) both converge to the Dirac distribution. Depending on what these functions are, it's possible to obtain f_n(x) g_n(x) \rightarrow 0, among many other results. The limit of the product depends on more than the limits of the individual sequences. It's not unique.

a X b = a+a+a+a+a+a+a+a+... (the sum has 'b' terms)

That only makes sense if b is an integer. But multiplication of distributions by integers is already defined (as is multiplication by arbitrary complex numbers).
 

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