Can Complex Numbers Be Ordered?

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Discussion Overview

The discussion centers around the question of whether complex numbers can be ordered in a manner similar to real numbers. Participants explore the implications of ordering complex numbers, including the effects on their algebraic structure and potential methods of ordering.

Discussion Character

  • Debate/contested
  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • Some participants note that while every set can be ordered, the relationship of such an order to the complex structure or linear/topological properties in ##\mathbb{R}^2## is questionable.
  • One participant argues that imposing an order on complex numbers would result in the loss of field properties.
  • Another participant explains that complex numbers do not allow an Archimedean order, citing the example of ##i^2 = -1 < 0## as a counterexample.
  • It is suggested that a lexicographical order could be defined for complex numbers, but this may not preserve desirable properties.
  • One participant presents an informal argument against the possibility of a total order on complex numbers, using the properties of inequalities and multiplication by complex numbers.
  • Another viewpoint proposes that a bijective function could be established between complex numbers and real numbers, allowing for some form of ordering, albeit without preserving nice properties.
  • A later reply mentions the possibility of well-ordering complex numbers, which imposes stronger conditions on the order.

Areas of Agreement / Disagreement

Participants express differing views on the nature and possibility of ordering complex numbers. There is no consensus on whether a meaningful order can be established that retains the properties of complex numbers.

Contextual Notes

Participants highlight limitations related to the definitions of order and the implications of ordering on the algebraic structure of complex numbers. The discussion reflects various assumptions about ordering and its consequences.

Arman777
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Can we order Complex Numbers ? I searched a bit most places says it can but not like the real numbers. I am confused a bit.And I am not sure abouth the truth of those sources.
Thanks
 
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We can order every set. But the question is will such an order have any relation to a complex structure or even to linear or topological structure in ##\mathbb{R}^2## :)
 
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If I recall correctly, the way it works is that if you try impose an order in the complex numbers, you then lose the field properties.
 
Arman777 said:
Can we order Complex Numbers ? I searched a bit most places says it can but not like the real numbers. I am confused a bit.And I am not sure abouth the truth of those sources.
Thanks
The complex numbers don't allow an Archimedean order. This is equivalent to the condition that squares are positive, which is not the case for complex numbers, as ##i^2=-1<0##. They allow however an order like the lexicographical order: ##x+iy < u+iv \Longleftrightarrow x < u \,\vee \, (x=u \wedge y < v)##.
 
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If you mean ordering like we think of ordering with real numbers, the answer is no. To demonstrate this, consider this example that uses an informal argument.

If ##\mathbb{C}## is a totally ordered set with properties like the real numbers, we have the axiom of totality, which says that ##\forall x,y \in \mathbb{C}: x \leq y## or ## x \geq y##

Thus, consider ##i \leq 0##, then multiply both sides with ##i##, obtaining ##-1 \geq 0## (multiplying with a number less than ##0## reverses the inequality sign). This is not possible.
Otherwise, assume ##i \geq 0##, then ##-1 \geq 0##. Also impossible.
 
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I understand thanks
 
You can find a bijective function between the complex numbers and the real numbers and then use the ordering of the real numbers to "order" the complex numbers. That won't lead to nice properties of the ordering, but it is some sort of order, similar to the one @fresh_42 suggested.

You can even have a well-ordering, which places stronger conditions on an order.
 

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