Can Compressions and Nodes Be Compared in Wave Calculations?

  • Thread starter Thread starter oooo
  • Start date Start date
  • Tags Tags
    Nodes
Click For Summary
Compressions and rarefactions in longitudinal waves cannot be directly compared to nodes and antinodes in standing waves. In a standing wave, the distance between consecutive nodes or antinodes is half the wavelength. However, in a traveling wave, the distance between consecutive compressions is equal to the full wavelength. Therefore, the initial assumption that the distance between compressions is half a wave is incorrect. Understanding this distinction is crucial for accurate wave calculations.
oooo
Messages
53
Reaction score
0
Just a quick question-- can compressions and rarefractions be compared to nodes and antinodes in calculations? For example, I have calculated the wavelength of a given longitudinal traveling wave and I am supposed to find the distance from one compression to an adjacent compression. I calculated this the same as you would from node to node where the distance between each is half a wave. However, when I tried this theory, (assuming that the distance between a compression and another compression is half a wave) it ended up being wrong. Please help soon-- I am reviewing for a Physics final tomorrow and came across this problem. I hope you can help clear it up. Thanks
 
Physics news on Phys.org
No
Nodes and antinodes are formed in a standing wave, not in a traveling wave.

The distance between two consecutive nodes (or antinodes) in a standing wave is half the wavelength.

The distance between to consecutive compression (or creasts in case of transverce waves) in a traveling wave is equal to wavelength.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 4 ·
Replies
4
Views
4K
Replies
17
Views
2K
Replies
20
Views
5K
  • · Replies 10 ·
Replies
10
Views
6K
Replies
16
Views
3K
Replies
10
Views
3K
  • · Replies 5 ·
Replies
5
Views
6K
Replies
1
Views
1K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K