Can Crafts Reach 2c Relative to Me?

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SUMMARY

The discussion centers on the concept of relative velocity in the context of special relativity, specifically addressing whether two hypothetical spacecraft can separate at a speed greater than the speed of light (2c) from an observer's perspective. It is established that while the observer measures the distance between the crafts as 372,000 miles apart after one second, the actual relative speed of separation cannot exceed the speed of light due to the principles of relativistic velocity addition. Instead, the separation speed is calculated as 2v/(1+v^2), where v is the speed of each craft, which remains less than c.

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Separation speed
Simple question for you guys. Thanks in advance for the help.

If you are standing on earth with a watch and hypothetical crafts to your left and right instantly take off 180 degrees apart at the speed of light, at the 1 second mark on YOUR watch they will be 372,000 miles apart. From YOUR perspective, it seems they should be moving apart at 2c. You measure the distance they traveled at its exactly as above. You were stationary and your watch clicked one second. It seems they had to be moving apart at 2c, but that would be the upper limit as to how fast they can move away from each other from your perspective. No laws are being broken as each craft is moving at c, not above it. From each crafts perspective I know it would be totally different. Is this correct or not? If its wrong, please explain how.
VERY much appreciated!
 
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That's correct, the upper limit for separation speed is ##2c##. Note that a massive spacecraft can't actually reach ##c## in your reference frame, but can get arbitrarily close to ##c##.
 
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Much appreciated. Its being argued on a different forum. :smile:
 
Abbott287287 said:
and right instantly take off 180 degrees apart at the speed of light,
That’s not possible, but we can fix this without changing the basic sense of your question by specifying that their speed relative to you is not ##c## but something like ##.99c##.

If one is moving to left at speed ##v\lt c## and the other is moving to the right at the same speed, you will observe them separating at speed ##2v \lt 2c##.

However, their speed relative to one another will be ##2v/(1+v^2)## which is less than ##c##. Google for “relativistic velocity addition” to see how I get that result.

(And note that I am measuring time in seconds and distances in light-seconds so that ##c=1##. This is a handy and very common, almost universal, trick for not cluttering the equations up with a whole bunch of ##c## and ##c^2## factors)
 
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