Can current through a resistor be negative and what does it mean?

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Sastronaut
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Homework Statement



Calculate the current through R3.

Homework Equations



V=IR

The Attempt at a Solution



my attempt is attached. My question revolves around my answer...is a negative current a legitimate answer? What does it mean?
 
Attachments
  • Handwritten circuit solution: a two-loop circuit with resistors R1, R2, R3 and voltage sources V1 and V2, with loop equations 5V + 20ΩI1 + 2ΩI3 = 0 and -10V - 2ΩI3 - 40ΩI2 = 0, and the result I1 = -.207A highlighted in yellow.
    phys.jpg
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It is a legitimate answer provided you show a direction arrow (which you have done). It means that the current is not traveling in the direction indicated by your direction arrow. It is going in the opposite direction.
 
Looking at your loop equations, they seem a bit suspect. If you are summing the changes in voltage across each element along a loop, equating the sum to zero, you should get something different.
 
Sastronaut said:

Homework Statement



Calculate the current through R3.

Homework Equations



V=IR

The Attempt at a Solution



my attempt is attached. My question revolves around my answer...is a negative current a legitimate answer? What does it mean?

Your equations 1 and 2 are wrong. Note, that the potential decreases in the direction of the current.

ehild
 
You start at the negative pole of the battery, and follow the change of potential in the direction, indicated by the green arrow. The potential increases by 5 V traversing the battery. Then it decreases by I3R3 along R3. Then again, it decreases by R1I1, when you return to your initial position. The net change of potential is zero: 5-I3R3-I1R1=0.
Do the same for the other loop. Note that going in direction opposite to the current, the potential would increase.

ehild

Handwritten circuit analysis: a two-loop resistor circuit diagram with V1 = 5V, V2 = 10V, R1 = 20 ohms, R2 = 40 ohms, R3 = 2 ohms, followed by loop equations and the result I1 = -.207A.
 
okay I think I am following you so for loop 2 the equation is then -10V+I3R3+I2R2=0?
 
Sastronaut said:
okay I think I am following you so for loop 2 the equation is then -10V+I3R3+I2R2=0?

Yes.

ehild