MHB Can Dividing by Sin x Help Prove Continuity at x = 0?

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Not sure how to do this question. Help needed. Thanks
 

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Another hint:
Use the well-known result $\displaystyle\lim_{x\to0}\frac{\sin x}x=1$.
 
Olinguito said:
Another hint:
Use the well-known result $\displaystyle\lim_{x\to0}\frac{\sin x}x=1$.


Given the hint that comes with the problem, I wouldn't think that would be appropriate. Alternatively one might suggest dividing everything by $\sin x$, which seems more in line with the hint.
 
We all know the definition of n-dimensional topological manifold uses open sets and homeomorphisms onto the image as open set in ##\mathbb R^n##. It should be possible to reformulate the definition of n-dimensional topological manifold using closed sets on the manifold's topology and on ##\mathbb R^n## ? I'm positive for this. Perhaps the definition of smooth manifold would be problematic, though.

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