Can force in Newtons be negative?

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Force in Newtons can be expressed as a negative value to indicate direction, but the magnitude itself is always positive. When calculating force using F=ma, the correct representation is |F| = m|a|, emphasizing that force is a vector with both magnitude and direction. Although some textbooks may present negative forces, this is misleading; the negative sign reflects the direction rather than a negative magnitude. Therefore, when calculating force from mass and acceleration, the answer should be stated as a positive value, such as 3000 Newtons. Understanding that force is a vector quantity is crucial for correctly interpreting its application in physics.
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Homework Statement



I am trying to find out if force in Newtons can be negative.

If i know the magnitude of decelaration of a car ( a minus acceleration ) and i know the mass, do i multiply the - acceleration value by the mass, resulting in a minus value in Newtons, or do i multiply the mass by the deceleration, resulting in a positive value in Newtons.

Homework Equations



for example, 1500kg ( mass ) x -2 m s-2 ( acceleration ) = -3000 Newtons

The Attempt at a Solution



I think this would be correct because the minus is telling us the direction in which the force is being applied, but i really am not sure, any advice would be appreciated?
 
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A force is a vector, it cannot have a negative magnitude. Although what you see as -3000 Newtons is really just a contradiction of the direction. The 3000 Newtons is acting in the direction opposite to the one you assumed it's acting in.

F=ma, should actually be |F|=m|a|, or \vec{F} = m \vec{a}

EDIT: Sorry, just read your attempt at solution. You're right, it corresponds to the direction.
 
Ahmedbasil said:
A force is a vector, it cannot have a negative magnitude. Although what you see as -3000 Newtons is really just a contradiction of the direction. The 3000 Newtons is acting in the direction opposite to the one you assumed it's acting in.

F=ma, should actually be |F|=m|a|, or \vec{F} = m \vec{a}

EDIT: Sorry, just read your attempt at solution. You're right, it corresponds to the direction.

Hi, thank you for your reply. So if i were to write the answer as -3000 Newtons would that be correct? Or should it be 3000?

Many thanks.
 
zoezoehzoe said:

Homework Statement



I am trying to find out if force in Newtons can be negative.

If i know the magnitude of decelaration of a car ( a minus acceleration ) and i know the mass, do i multiply the - acceleration value by the mass, resulting in a minus value in Newtons, or do i multiply the mass by the deceleration, resulting in a positive value in Newtons.

Homework Equations



for example, 1500kg ( mass ) x -2 m s-2 ( acceleration ) = -3000 Newtons

The Attempt at a Solution



I think this would be correct because the minus is telling us the direction in which the force is being applied, but i really am not sure, any advice would be appreciated?

Hiii zoezoehzoe !

Force is a vector quantity but that doesn't even mean that it has to be negative. However I came across some textbooks which claim the answers in -500 N etc. It is not a big deal but this is not correct. It is wrong ! As Ahmedbasil said that force is vector because of direction. It has magnitude as well as direction.

|F| = m x |a| ---> This is a correct representation.

Cross product of vector(acceleration) and scalar(mass) is always vector(force).

Vector quantity : Direction + Magnitude + can be negative or remain absolute OR only magnitude but negative ; Example: Displacement , acceleration , velocity etc .

Scalar quantity :Only Magnitude ;and only positive . Eg. Distance , speed , mass etc .

In F=ma , acceleration has nothing to do with direction even. It just tells increase or decrease in velocity per unit time. Force is dependent on direction. Example : Centripetal force in centre due to constant change in direction.

I recommend you should write 3000 N as your answer.
___________________________________________________________
Ahmedbasil , you are correct to say that -X N means force is applied in opposite direction but you must not say that it is because it is causing retardation in opposite direction. Retardation = -(-Acceleration).
Positive and negative sign in acceleration just tell that whether speed is increasing (velocity for particular) or decreasing.

:wink:

Always feel free to ask questions. Well done !
 
Last edited:
sankalpmittal said:
Hiii zoezoehzoe !

Force is a vector quantity but that doesn't even mean that it has to be negative. However I came across some textbooks which claim the answers in -500 N etc. It is not a big deal but this is not correct. It is wrong ! As Ahmedbasil said that force is vector because of direction. It has magnitude as well as direction.

|F| = m x |a| ---> This is a correct representation.

Cross product of vector(acceleration) and scalar(mass) is always vector(force).

Vector quantity : Direction + Magnitude + can be negative or remain absolute OR only magnitude but negative ; Example: Displacement , acceleration , velocity etc .

Scalar quantity :Only Magnitude ;and only positive . Eg. Distance , speed , mass etc .

In F=ma , acceleration has nothing to do with direction even. It just tells increase or decrease in velocity per unit time. Force is dependent on direction. Example : Centripetal force in centre due to constant change in direction.

I recommend you should write 3000 N as your answer.

:wink:

Thank you both very much for your help :)
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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