- #1

- 1,169

- 132

- Homework Statement
- Please see below

- Relevant Equations
- Newton Second Law

I am trying to verify Newton II. The setup I am using is,

Where ##m_1 = 0.887 kg## is a cart and ##m_2 = 0.02016 kg## is a small hanging mass. There is a force sensor on ##m_1## to measure the force acting on it from the string and the acceleration of the cart.

To verify Newton's Second Law, we tried to plot we plot acceleration of ##m_2## vs force ##F## which is the same as the tension ##T##.

Apply Newton II to the ##m_2##: ##T = m_2a + m_2g## which is a linear equation (##y = mx + c##) of the form,

which is of the form ##y = T, m = m_2, x = a## and ##c = m_2g##

Therefore we graphed T vs a to get:

However, do you please know why I am getting ##m_2 = -0.2152 kg## from the graph when we measure it to be 0.02kg? I am not sure why the negative sign and why it is x10 larger than the measured ##m_2##. Also when I solve ##c = 0.5069 = m_2g##, for ##m_2## I also get a very different value for ##m_2##

Any help greatly appreciated!

Many thanks!

Where ##m_1 = 0.887 kg## is a cart and ##m_2 = 0.02016 kg## is a small hanging mass. There is a force sensor on ##m_1## to measure the force acting on it from the string and the acceleration of the cart.

To verify Newton's Second Law, we tried to plot we plot acceleration of ##m_2## vs force ##F## which is the same as the tension ##T##.

Apply Newton II to the ##m_2##: ##T = m_2a + m_2g## which is a linear equation (##y = mx + c##) of the form,

which is of the form ##y = T, m = m_2, x = a## and ##c = m_2g##

Therefore we graphed T vs a to get:

However, do you please know why I am getting ##m_2 = -0.2152 kg## from the graph when we measure it to be 0.02kg? I am not sure why the negative sign and why it is x10 larger than the measured ##m_2##. Also when I solve ##c = 0.5069 = m_2g##, for ##m_2## I also get a very different value for ##m_2##

Any help greatly appreciated!

Many thanks!