Can force in Newtons be negative?

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Homework Help Overview

The discussion revolves around whether force, measured in Newtons, can be negative, particularly in the context of a car's deceleration. The original poster is exploring the relationship between mass, acceleration, and the resulting force, questioning how to interpret negative acceleration in calculations.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the nature of force as a vector quantity and whether negative values can be used to indicate direction. The original poster questions if multiplying mass by negative acceleration results in a negative force or if it should be expressed positively.

Discussion Status

Some participants have provided insights into the vector nature of force and its dependence on direction. There is a recognition of differing interpretations regarding the representation of force values, with suggestions to consider absolute values in certain contexts. However, there is no explicit consensus on how to express the final answer.

Contextual Notes

Participants reference various textbooks and their differing conventions regarding negative force values, indicating a lack of uniformity in educational resources. The discussion also touches on the definitions of vector and scalar quantities, which may influence understanding of the problem.

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Homework Statement



I am trying to find out if force in Newtons can be negative.

If i know the magnitude of decelaration of a car ( a minus acceleration ) and i know the mass, do i multiply the - acceleration value by the mass, resulting in a minus value in Newtons, or do i multiply the mass by the deceleration, resulting in a positive value in Newtons.

Homework Equations



for example, 1500kg ( mass ) x -2 m s-2 ( acceleration ) = -3000 Newtons

The Attempt at a Solution



I think this would be correct because the minus is telling us the direction in which the force is being applied, but i really am not sure, any advice would be appreciated?
 
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A force is a vector, it cannot have a negative magnitude. Although what you see as -3000 Newtons is really just a contradiction of the direction. The 3000 Newtons is acting in the direction opposite to the one you assumed it's acting in.

F=ma, should actually be |F|=m|a|, or \vec{F} = m \vec{a}

EDIT: Sorry, just read your attempt at solution. You're right, it corresponds to the direction.
 
Ahmedbasil said:
A force is a vector, it cannot have a negative magnitude. Although what you see as -3000 Newtons is really just a contradiction of the direction. The 3000 Newtons is acting in the direction opposite to the one you assumed it's acting in.

F=ma, should actually be |F|=m|a|, or \vec{F} = m \vec{a}

EDIT: Sorry, just read your attempt at solution. You're right, it corresponds to the direction.

Hi, thank you for your reply. So if i were to write the answer as -3000 Newtons would that be correct? Or should it be 3000?

Many thanks.
 
zoezoehzoe said:

Homework Statement



I am trying to find out if force in Newtons can be negative.

If i know the magnitude of decelaration of a car ( a minus acceleration ) and i know the mass, do i multiply the - acceleration value by the mass, resulting in a minus value in Newtons, or do i multiply the mass by the deceleration, resulting in a positive value in Newtons.

Homework Equations



for example, 1500kg ( mass ) x -2 m s-2 ( acceleration ) = -3000 Newtons

The Attempt at a Solution



I think this would be correct because the minus is telling us the direction in which the force is being applied, but i really am not sure, any advice would be appreciated?

Hiii zoezoehzoe !

Force is a vector quantity but that doesn't even mean that it has to be negative. However I came across some textbooks which claim the answers in -500 N etc. It is not a big deal but this is not correct. It is wrong ! As Ahmedbasil said that force is vector because of direction. It has magnitude as well as direction.

|F| = m x |a| ---> This is a correct representation.

Cross product of vector(acceleration) and scalar(mass) is always vector(force).

Vector quantity : Direction + Magnitude + can be negative or remain absolute OR only magnitude but negative ; Example: Displacement , acceleration , velocity etc .

Scalar quantity :Only Magnitude ;and only positive . Eg. Distance , speed , mass etc .

In F=ma , acceleration has nothing to do with direction even. It just tells increase or decrease in velocity per unit time. Force is dependent on direction. Example : Centripetal force in centre due to constant change in direction.

I recommend you should write 3000 N as your answer.
___________________________________________________________
Ahmedbasil , you are correct to say that -X N means force is applied in opposite direction but you must not say that it is because it is causing retardation in opposite direction. Retardation = -(-Acceleration).
Positive and negative sign in acceleration just tell that whether speed is increasing (velocity for particular) or decreasing.

:wink:

Always feel free to ask questions. Well done !
 
Last edited:
sankalpmittal said:
Hiii zoezoehzoe !

Force is a vector quantity but that doesn't even mean that it has to be negative. However I came across some textbooks which claim the answers in -500 N etc. It is not a big deal but this is not correct. It is wrong ! As Ahmedbasil said that force is vector because of direction. It has magnitude as well as direction.

|F| = m x |a| ---> This is a correct representation.

Cross product of vector(acceleration) and scalar(mass) is always vector(force).

Vector quantity : Direction + Magnitude + can be negative or remain absolute OR only magnitude but negative ; Example: Displacement , acceleration , velocity etc .

Scalar quantity :Only Magnitude ;and only positive . Eg. Distance , speed , mass etc .

In F=ma , acceleration has nothing to do with direction even. It just tells increase or decrease in velocity per unit time. Force is dependent on direction. Example : Centripetal force in centre due to constant change in direction.

I recommend you should write 3000 N as your answer.

:wink:

Thank you both very much for your help :)
 

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