Can Graphing Reveal All Solutions to Complex Polynomial Systems?

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Discussion Overview

The discussion centers around solving a system of complex polynomial equations, specifically the equations {5x^4 - 4x + 5y = 0, 5y^4 + 5x - 4y = 0}. Participants explore methods to find all solutions, including the known solution (0,0) and potentially others.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Exploratory

Main Points Raised

  • One participant presents the system of equations and mentions (0,0) as a known solution, seeking assistance to demonstrate it and find additional solutions.
  • Another participant suggests subtracting the equations to derive a new equation, which can be factored, indicating a potential path to find solutions.
  • A later reply introduces the use of Groebner basis methods via a computer algebra system (Maple 11) to obtain all solutions, detailing the steps taken to factor the resulting polynomial.
  • The factoring of the polynomial yields specific roots for y, which can then be used to find corresponding x values, emphasizing the complexity of manual calculations compared to using computational tools.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the methods or completeness of the solutions, with multiple approaches and techniques being discussed without resolution of which is superior.

Contextual Notes

The discussion highlights the complexity of solving the polynomial system, with participants acknowledging the potential for extraneous roots and the necessity of verification against the original equations.

lape99
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I don't know if I'm posting in the wright section, but i need to solve this system of equations:

{5x^4 - 4x + 5y = 0
5y^4 + 5x - 4y = 0}

I know one answer is (0;0), but i don't know how to show it, also there is another point.
Maybe someone can help me?
 
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If you subtract the equations from each other, you get the following:

5x^4-5y^4-9(x-y)=0

Now, you have:
x^4-y^4=(x-y)(x^3+x^2y+xy^2+y^3), and thus, you may factorize the above equation as:
(x-y)*(5(x^3+x^2y+xy^2+y^3)-9)=0
 
Thank you very much :)
 
lape99 said:
I don't know if I'm posting in the wright section, but i need to solve this system of equations:

{5x^4 - 4x + 5y = 0
5y^4 + 5x - 4y = 0}

I know one answer is (0;0), but i don't know how to show it, also there is another point.
Maybe someone can help me?

One can use Groebner basis methods to get at all the solutions. Using the Groebner package in Maple 11, I get:
sys:=[5*x^4-4*x+5*y,5*y^4+5*x-4*y]:lprint(sys); <== input
[5*x^4-4*x+5*y, 5*y^4+5*x-4*y]
with(Groebner): <=== load the Groebner package
B:=Basis(sys,plex(x,y)):lprint(B);
[225*y+756*y^4-1280*y^7+2400*y^10-2000*y^13+625*y^16, 5*y^4+5*x-4*y]

This B is the output. The two original equations are equivalent to setting the two components of B to zero (although, of course, there may be some extraneous roots, so those must be checked in the original system). Note that the first component of B is a polynomial in y alone, so we can find roots of the two-equation system by first solving the polynomial in y, then solving for x by setting the second expression in B to zero.

f1y:=B[1]:lprint(f1y);
225*y+756*y^4-1280*y^7+2400*y^10-2000*y^13+625*y^16 <--- set to zero

Let's try to factor the polynomial.

F:=factor(f1y):lprint(F);
y*(5*y^3+1)*(125*y^12-425*y^9+565*y^6-369*y^3+225) <=== the factors

So, y = 0 or 5*y^3 + 1 = 0, or
125*y^12 -425*y^9 + 565*y^6 -360*y^3 + 225 = 0, which is a 4th degree polynomial in z = y^3.

After solving for y, we get x from 5*x = 4*y - 5*y^4.

Note: doing anything like this by hand would take months or years of work and require hundreds of pages of algebraic work. Use of a computer algebra system is essential.

RGV
 

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