Can Hedges' g be greater than 1 for paired t-tests?

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SUMMARY

Hedges' g can indeed exceed 1 in the context of paired t-tests when calculated using the formula g = (mean_G1 - mean_G2) / (mean of standard deviation_G1 and standard deviation_G2). This formula emphasizes the importance of accurately defining "average standard deviation" as the mean of the standard deviations of the two related datasets. In practical applications, such as comparing test scores before and after studying, a Hedges' g greater than 1 indicates a substantial effect size, reflecting a significant difference between the two means.

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  • Familiarity with effect size calculations, specifically Hedges' g
  • Knowledge of standard deviation and its significance in statistical analysis
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  • Study the derivation and interpretation of Hedges' g in various statistical contexts
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  • Explore the differences between Hedges' g and Cohen's d for effect size measurement
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Researchers, statisticians, and educators interested in understanding effect sizes in paired sample analyses, particularly in fields such as psychology and education.

Soaring Crane
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Can Hedges' g (effect size) for a paired t-test be greater than 1 if the following is the formula for g?


g = (mean_1 - mean_2)/(average standard deviation of the two variables)

Thank you.
 
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You should define what you mean by "average standard deviation of the two variables". (And you shouldn't say ithe things involved are parameters of "the variables" if you actually mean the things involved are quantities calculated from a sample.)
 
If you have a data set comprised of test scores before studying (G1) and a data set comprised of test scores after studying (G2),

formula would read as:

g = (mean_G1 - mean_G2)/(mean of standard deviation_G1 and standard deviation_G2).

Thank you.
 

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