Volatility of investment (/w currency hedging)

Click For Summary
SUMMARY

The discussion focuses on calculating the volatility of an investment that includes currency hedging, specifically using the S&P 500 index with a volatility of 16% and a currency volatility of 5%. The correct method to compute the overall volatility is through the formula $$\sigma=\sqrt{(16^2)+(5^2)}$$, which adds the variances of the independent volatilities. The conversation clarifies that while deviations can be multiplied in certain contexts, for independent variables, the variances must be added to accurately reflect the total volatility.

PREREQUISITES
  • Understanding of financial volatility concepts
  • Familiarity with the S&P 500 index
  • Basic knowledge of variance and standard deviation
  • Experience with currency hedging strategies
NEXT STEPS
  • Research the implications of independent variables in financial volatility calculations
  • Learn about advanced currency hedging techniques
  • Explore the mathematical principles behind variance and standard deviation
  • Study the impact of market conditions on the S&P 500 index volatility
USEFUL FOR

Investors, financial analysts, and risk management professionals seeking to understand the complexities of investment volatility and currency hedging strategies.

egikm
Messages
2
Reaction score
0
I´ve been trying to compute a volatility of invesment with currency hedging and I have a question. Let's take this example. We have our money in a fond copying the S&P500 index, which has 16% volatility, we also know that the current volatility of a dollar toward our currency is 5%. We want to know the volatility of the whole invesment.

Can I compute as following? If so, what is the reason for adding the two deviations instead of mulitplying them considering the volalitity of an index and a currency are mutualy independent.

$$\sigma=\sqrt{(16^2)+(5^2)}$$

Thank you.
 
Physics news on Phys.org
How would multiplying them make sense? If one gets fixed, do you lose all volatility?

What you can multiply are the actual courses, e.g. for deviations like (1+0.16)*(1+0.05) = 1+0.16+0.05+0.16*0.05. Neglect the last term, and you see that the deviations add.
If the deviations become large, neglecting the last term does not work any more.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 16 ·
Replies
16
Views
5K
  • · Replies 0 ·
Replies
0
Views
4K
  • · Replies 2 ·
Replies
2
Views
618
Replies
1
Views
3K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 13 ·
Replies
13
Views
4K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 7 ·
Replies
7
Views
4K