Can I Calculate Salt Concentration in a 1500kg/m^3 Solution Using Density?

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Discussion Overview

The discussion revolves around calculating the concentration of salt in a solution with a specified density of 1500 kg/m³, formed by mixing 50 kg of salt with 100 kg of water. Participants explore whether the concentration can be determined by subtracting the density of water or through other calculations, while also questioning the assumptions about the volumes involved.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • Some participants question whether the density of the solution can be directly used to calculate the concentration of salt, suggesting that the volume of salt may not be negligible.
  • Others propose that the concentration can be calculated using the formula 50/((50+100)/1500) to find the concentration in kg/m³.
  • There is a discussion about the definition of concentration and how it can vary based on the method used.
  • Some participants express skepticism about the assumption that the density of the solution is known and challenge the idea that density is additive in this context.
  • A later reply introduces the concept of partial molal volumes, suggesting complexities in the solution process that may not be accounted for in simple calculations.

Areas of Agreement / Disagreement

Participants do not reach a consensus on how to calculate the concentration of salt in the solution. Multiple competing views and uncertainties about the assumptions regarding density and volume remain unresolved.

Contextual Notes

Limitations include assumptions about the additivity of densities and the negligible volume of salt, which may not hold true in all cases. The discussion highlights the complexity of defining and calculating concentration in solutions.

Supernova123
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If 50kg of salt is mixed with 100 kg of water to form a 1500kg/m^3 solution, can I find the concentration of salt by subtracting the density of water which is 1000kg/m^3, or do I have to equate it like this: 50/((50+100)/1500)=500kg/m^3 ? Is the volume of salt negligible so that the volume of solution equals the volume of water?
 
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Supernova123 said:
If 50kg of salt is mixed with 100 kg of water to form a 1500kg/m^3 solution, can I find the concentration of salt by subtracting the density of water which is 1000kg/m^3, or do I have to equate it like this: 50/((50+100)/1500)=500kg/m^3 ? Is the volume of salt negligible so that the volume of solution equals the volume of water?
The concentration of a solution can be defined in several different ways. Here are some of them:

https://www.chem.purdue.edu/gchelp/howtosolveit/Solutions/concentrations.html

The density of most salts is often greater than that of water. For common table salt, NaCl, its density is 2.17 g/cc (water = 1.0 g/cc)

https://en.wikipedia.org/wiki/Sodium_chloride

Your example solution has a final density of 1500 kg/m3. Since you know that 50 kg of salt is mixed with 100 kg of water, you should be able to figure out the volume of solution created, since the total mass of solution must equal the total mass of the stuff being mixed together.

For more information about solutions:

https://en.wikipedia.org/wiki/Solution
 
Supernova123 said:
If 50kg of salt is mixed with 100 kg of water to form a 1500kg/m^3 solution

How do you know that's the density of the solution produced?
 
Borek said:
How do you know that's the density of the solution produced?
You don't, but that's what the OP said.
 
SteamKing said:
You don't, but that's what the OP said.

I wonder if OP doesn't think density is in some strange way additive.
 
The solution process is magical, partial molal volumes of solutes are all zero.
 

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