Can I Graph a Semicircle By Hand?

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Discussion Overview

The discussion revolves around the process of graphing a semicircle defined by the equation of a circle. Participants explore whether it is feasible to graph the semicircle by hand and seek guidance on identifying specific points to aid in the drawing process.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant presents the equation of a circle and asks if it can be graphed by hand or if a graphing tool should be used.
  • Another participant identifies the center of the circle as $(4,1)$ and the radius as $r=3$, providing three specific points on the upper semicircle: $(7,1)$, $(4,4)$, and $(1,1)$.
  • A participant expresses confusion about how the three points were derived, prompting clarification about their positions relative to the circle's center.
  • Clarification is provided that the points are determined by moving 3 units in different directions from the center of the circle.
  • A later reply indicates understanding and appreciation for the explanation given about the points.

Areas of Agreement / Disagreement

Participants generally agree on the identification of the center and radius of the circle, as well as the points to plot for the semicircle. However, there is some confusion regarding the derivation of these points, which is clarified but not fully resolved.

Contextual Notes

The discussion does not address potential limitations in the graphing process or any assumptions made about the semicircle's orientation.

mathdad
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An equation of the circle is given below. Solve the equation for y, and then graph the resulting semicircle.

(x - 4)^2 + (y - 1)^2 = 9

I must isolate y. I get it. My question concerns graphing the semicircle by hand. Can it be graphed by hand or should I simply use the wolfram math site for graphing? If by hand, can you provide several points that would allow me to draw the semicircle correctly?
 
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You know the center of the circle is $(4,1)$ amd the radius is $r=3$. So, this gives you 3 easy points (if you choose the "upper" semi-circle):

$(4+3,1)=(7,1))$

$(4,1+3)=(4,4)$

$(4-3,1)=(1,1)$

Then connect the 3 points with a circular arc.
 
MarkFL said:
You know the center of the circle is $(4,1)$ amd the radius is $r=3$. So, this gives you 3 easy points (if you choose the "upper" semi-circle):

$(4+3,1)=(7,1))$

$(4,1+3)=(4,4)$

$(4-3,1)=(1,1)$

Then connect the 3 points with a circular arc.

Plotting the three points is easy but I am slightly confused in terms of how you came up with the points.
 
RTCNTC said:
Plotting the three points is easy but I am slightly confused in terms of how you came up with the points.

The first point is 3 units to the right of the circle's center, the second point is 3 units up and the third point is 3 units to the left. :D
 
MarkFL said:
The first point is 3 units to the right of the circle's center, the second point is 3 units up and the third point is 3 units to the left. :D

I totally get it. Thanks again.
 

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