The capacitor has a reactance Rc to AC, which is pretty much similar to resistance in DC.
Rc = I/wC, where w = 2(pi)f. In analogy with DC, V = I*Rc => I = 2(pi)VfC, where V and I are actually the RMS values. V and f are set by the power companies, and you can't do anything about them.
By making C high, you can increase I. To blow a fuse, you need around 5 A of current. Now do the math for what C you need.
SO, when are you planning to do it?