Can I use the theorem for solving the given inequality?

  • Context: MHB 
  • Thread starter Thread starter mathdad
  • Start date Start date
  • Tags Tags
    Inequality
Click For Summary

Discussion Overview

The discussion revolves around the application of a theorem related to absolute values in solving an inequality involving a linear expression. Participants explore whether the theorem can be appropriately applied to the given inequality and share their approaches to manipulating the expression.

Discussion Character

  • Homework-related, Mathematical reasoning

Main Points Raised

  • One participant questions the applicability of the theorem stating that if a > 0, then |u| < a if and only if -a < u < a.
  • Another participant confirms the applicability of the theorem with a simple affirmation.
  • A third participant elaborates on the solution process by multiplying through by 12, leading to a reformulation of the inequality and expressing the solution in terms of distance from a specific point on the number line.
  • A final participant expresses gratitude and indicates they can continue from the provided information.

Areas of Agreement / Disagreement

There is no clear consensus on the applicability of the theorem, as participants provide varying levels of affirmation and elaboration on the problem without resolving the initial question.

Contextual Notes

Some assumptions regarding the manipulation of the inequality and the conditions under which the theorem applies are not explicitly stated, leaving room for interpretation.

Who May Find This Useful

Students or individuals working on inequalities and absolute value theorems in mathematics may find this discussion relevant.

mathdad
Messages
1,280
Reaction score
0
|[3(x - 2)/4] + 4(x - 1)/3| ≤ 2

Can I use the following theorem?

If a > 0, then | u | < a if and only if -a < u < a
 
Mathematics news on Phys.org
RTCNTC said:
|[3(x - 2)/4] + 4(x - 1)/3| ≤ 2

Can I use the following theorem?

If a > 0, then | u | < a if and only if -a < u < a

yes
 
RTCNTC said:
|[3(x - 2)/4] + 4(x - 1)/3| ≤ 2

Can I use the following theorem?

If a > 0, then | u | < a if and only if -a < u < a

I'd begin by multiplying through by 12 to get:

$$\left|9(x-2)+16(x-1)\right|\le24$$

$$|25x-34|\le24$$

$$\left|x-\frac{34}{25}\right|\le\frac{24}{25}$$

Now it's obvious the solution is the set of all real numbers whose distance on the number line from 34/25 is less than or equal to 24/25...:D
 
Thank you. I can take it from here.
 

Similar threads

  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 0 ·
Replies
0
Views
627
  • · Replies 2 ·
Replies
2
Views
1K