- #1

dyn

- 773

- 61

If i have the inequality , 9 > x

^{2}then i know the answer is , -3 < x < +3 but my confusion lies in the following ; if i take the square root of both sides of the inequality i get , ± 3 > ±x

Is that correct ? If so , it leads to the following solutions

x < 3 , x > -3 , x < -3 , x >3 ; which i know is wrong but why ?

Thanks