Can Limits to Infinity Prove a Zero Derivative Over the Reals?

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JPBenowitz
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Suppose I have

limt[itex]\rightarrow∞[/itex] f(g(t)) = 0

and

limt[itex]\rightarrow-∞[/itex] f(g(t)) = 0

How would I prove [itex]\frac{df}{dt}[/itex][itex]_{|}\Re[/itex] = 0? (over the reals)
 
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This question doesn't make sense. Could you provide some context?
 
theorem4.5.9 said:
This question doesn't make sense. Could you provide some context?

I'm having problems displaying what I want to convey. Basically I proved that the limit for the curvature function will always converge to zero for any real continuous function and now I want to prove that the derivative with respect to time will always converge to zero.

So, essentially I need to prove that the integral over the reals of the curvature function will always converge to some constant.