Can Linear Expansion Formula Be Used for a Heated Brass Spring?

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SUMMARY

The discussion focuses on the application of the linear expansion formula to calculate the compressional force required to restore a heated brass spring to its original length. The user correctly applies the linear expansion formula, using a coefficient of linear expansion for brass (9 x 10^-6) and finds a change in length of 3.89 x 10^-4 m. Subsequently, they utilize Hooke's Law (F = k * ΔL) with a spring constant of 1.3 x 10^4 N/m to determine the compressional force, resulting in a force of 5.07 N. This approach is validated as correct for the problem presented.

PREREQUISITES
  • Understanding of linear expansion principles
  • Familiarity with Hooke's Law and spring constants
  • Basic knowledge of temperature effects on materials
  • Ability to perform calculations involving coefficients of linear expansion
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Mechanical engineers, materials scientists, and physics students interested in the thermal properties of materials and their applications in spring mechanics.

rsyodoom2005
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1. A brass spring has an unstrained length of .18m and a spring constant of 1.3 E4 N/m. THe temperature increases from 21 cel to 135 cel. what is the magnitude of the compressional force that must be applied to the heated spring to bring it back to its original lenght!?



2. Linear expansion; Change of lenght= constant *lenght * change of temp
F= K Change of lenght




the thing i am concern is with Linear expansion formula can i use this fromula for the spring?! I figure out my change of length first my multyplying my coeficcient of brass
(9*10^-6)* .18m * 135-21 to get a result of 3.89*10^-4

Then i clicked it on to the spring constan formula using F= 1.3*10^4 * the distance of 3.89*10^-4 to myforce of 5.07N... is this a right approach?
 
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Must be correct.I don't think that this question needs more complicated solution.
 

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