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BuBbLeS01
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Quick question...can normal force be negative when calculating apparent weight?
n (top) = (mv^2/r) - w
n (top) = (mv^2/r) - w
Can Normal Force Be Negative in Apparent Weight Calculations?
- Thread starter BuBbLeS01
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- Apparent weight Circle Weight
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SUMMARY
The discussion confirms that the normal force can indeed be negative when calculating apparent weight, particularly in scenarios involving vertical loops. The equation n (top) = (mv^2/r) - w illustrates this concept, where 'n' represents the normal force, 'm' is mass, 'v' is velocity, 'r' is the radius of the loop, and 'w' is the weight. At the top of a vertical loop, the weight acts downward and opposes the centrifugal force, leading to a situation where the normal force may become negative.
PREREQUISITES- Understanding of Newton's laws of motion
- Familiarity with circular motion concepts
- Basic knowledge of forces and weight calculations
- Proficiency in algebra for manipulating equations
- Study the principles of circular motion in physics
- Learn about the effects of centripetal force on objects in motion
- Explore advanced topics in dynamics related to forces
- Investigate real-world applications of apparent weight in roller coasters
Physics students, educators, and engineers interested in dynamics and the behavior of forces in motion, particularly in scenarios involving circular paths.
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