Can open sets be described in-terms of closed sets?

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Discussion Overview

The discussion revolves around the characterization of open sets in terms of closed sets, specifically examining whether an open interval can be defined using closed intervals. The scope includes theoretical exploration and mathematical reasoning.

Discussion Character

  • Exploratory, Mathematical reasoning

Main Points Raised

  • One participant proposes that an open set A, defined as (a,b), can be described using closed sets by stating that for every x>0, all elements of the closed set [a+x,b-x] are elements of A.
  • Another participant clarifies that the statement implies ##\forall x>0##, ##[a+x, b-x] \subset A##, which they assert is true.
  • However, the same participant notes that ##\forall x>0##, ##[a+x, b-x] \subset [a,b]## is also true, suggesting that this definition is insufficient for A.
  • A later reply suggests that A could be described as the union of all intervals [a+x,b-x] for x>0, or as the smallest set containing those intervals.
  • Another participant agrees with the union approach, emphasizing that without the union, each interval (a+x,b-x) remains a subset of both (a,b) and [a,b].

Areas of Agreement / Disagreement

Participants express differing views on the adequacy of using closed sets to define open sets, with some proposing alternative definitions while others highlight limitations in the initial approach. The discussion remains unresolved regarding the best characterization.

Contextual Notes

Participants acknowledge that the definitions depend on the choice of intervals and the implications of union versus individual sets. There is an implicit assumption about the nature of open and closed sets that is not fully explored.

Alpharup
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Let A be an open set and A=(a,b). Can A be described, as closed set as
"or every x>0, all the elements of closed set [a+x,b-x] are elements of A"?
 
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The statement in quotes means
##\forall x>0##, ##[a+x, b-x] \subset A##,
which is a true statement.

But
##\forall x>0##, ##[a+x, b-x] \subset [a,b]##
is also a true statement, so you can't use it to define A.
 
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Yes you are right...It just becomes a subset. But is there any way to describe it?
 
Sure. For example, let "A be the union of all ##[a+x,b-x]## with ##x>0##." Or "A is the smallest set that contain ##[a+x,b-x]## with ##x>0##".
 
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Yes,,,,the union part...If there were no union, every set (a+x,b-x) is a subset of both (a,b) and [a,b]
 

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