Can someone check pf: If y element reals and (y+1)/(y-2)=x, then x≠1

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The discussion centers on the mathematical proof that if \( y \) is a real number and \( \frac{y+1}{y-2} = x \), then \( x \neq 1 \). The proof employs a contradiction method, assuming \( x = 1 \) leads to the false statement \( 1 = -2 \). This confirms that the original equation cannot equal 1, establishing the conclusion definitively.

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Homework Statement


If y element of Reals and (y+1)/y-2) = x, then x ≠ 1.


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The Attempt at a Solution


Proof by contradiction. Assume x = 1. Then y + 1 = y -2 or 1 = -2. This is false. It contradicts (y+1)/(y-2)= x. Therefore, x ≠ 1.
 
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