Can someone Check this (Energy Question)

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Homework Help Overview

The discussion revolves around calculating the total energy of a geosynchronous satellite, specifically focusing on the gravitational potential energy and kinetic energy involved in the satellite's orbit around the Earth.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to calculate total energy using the formulas for gravitational potential energy and kinetic energy, but questions the validity of their calculations. Some participants raise concerns about the appropriateness of using the formula for gravitational potential energy at the satellite's height, while others suggest looking up the general expression for gravitational potential energy.

Discussion Status

Participants are exploring different interpretations of gravitational potential energy at higher altitudes. Guidance has been offered regarding the limitations of the mgh formula, and there is an ongoing examination of the correct expression for gravitational potential energy in this context.

Contextual Notes

There is a noted concern about the validity of using g = 9.8 m/s² at the satellite's altitude, prompting questions about the gravitational potential energy at that height.

quickslant
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Q: Calculate the total engery of a geosynchonous satellite (one that orbits over a fixed spot) with amass of 1500 kg, orbiting Earth at height 325 km (325 000m) with an orbital speed of 5000 m/s or 5.0x10^3

My Solution: Et = Ep + Ek
Ep = Mg delta H
Ek = 1/2 (m) V^2
thus Et = Mg(H) + 1/2 (m) v^2
(1500)(9.8)(325000) + 1/2(1500) (5000)^2
= 4.78x10^9 + 1.875x10^10
=2.353x10^10 j or 2.353x10^7 Kj

Is there a mistake in my calculations or has this question been done correctly?
 
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quickslant said:
Q: Calculate the total engery of a geosynchonous satellite (one that orbits over a fixed spot) with amass of 1500 kg, orbiting Earth at height 325 km (325 000m) with an orbital speed of 5000 m/s or 5.0x10^3

My Solution: Et = Ep + Ek
Ep = Mg delta H
Ek = 1/2 (m) V^2
thus Et = Mg(H) + 1/2 (m) v^2
(1500)(9.8)(325000) + 1/2(1500) (5000)^2
= 4.78x10^9 + 1.875x10^10
=2.353x10^10 j or 2.353x10^7 Kj

Is there a mistake in my calculations or has this question been done correctly?
using g = 9.8m/s/s is valid only near earth. What can you say about GPE at those heights?
 
i have no idea? is it 0? or is it very small? i have no idea
 
Look up the general expression for the gravitational PE between two masses (such as the Earth and a satellite).

As PhanthomJay pointed out, mgh is only useful for finding changes in PE for objects close to the surface of the earth.
 
ok.. Ep = Gm1m2/r
 
quickslant said:
ok.. Ep = Gm1m2/r
Don't forget the minus sign: Ep = -Gm1m2/r
 
ok thank you
 

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