- #1

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s^2 = 4^2 + 9^2

s^2 = 377

s = 19.4 mph

Ө = Tan^(-1) [ 19/4 ] = 78.1°

3 figure bearing is thus 180 ° - 78.1 ° = 101.9 °

109.1 ° = N 11.9 ° W

Why 109.1 ° = N 11.9 ° W.

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- #1

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s^2 = 4^2 + 9^2

s^2 = 377

s = 19.4 mph

Ө = Tan^(-1) [ 19/4 ] = 78.1°

3 figure bearing is thus 180 ° - 78.1 ° = 101.9 °

109.1 ° = N 11.9 ° W

Why 109.1 ° = N 11.9 ° W.

- #2

statdad

Homework Helper

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It isn't: the result is [tex] 101.9^\circ[/tex], not [tex] 109.1^\circ [/tex]. With N at [tex] 90^\circ [/tex], the result is [tex] 11.9^\circ [/tex] west of that, hence the [tex] N 11.9^\circ W [/tex].Let speed be s

s^2 = 4^2 + 9^2

s^2 = 377

s = 19.4 mph

Ө = Tan^(-1) [ 19/4 ] = 78.1°

3 figure bearing is thus 180 ° - 78.1 ° = 101.9 °

109.1 ° = N 11.9 ° W.

Why 109.1 ° = N 11.9 ° W.

- #3

- 40

- 0

Oh man! So stupid of me. Thanks!

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