A stone is thrown vertically upward at a speed of 18.00 m/s at time t=0. A second stone is thrown upward with the same speed 0.880 s later. (a) At what time are the two stones at the same height? (b) At what height do the two stones pass each other? (c) What is the upward speed of the second stone as they pass each other? (d) What is the downward speed of the first stone as they pass each other? I'm at a complete loss for this. I know stone one will be traveling down and stone two will be traveling up when they are at the same height, but how do I find that exact height. Here are the formulas I'm allowed to work with. Xf = Xi + VT Vf = Vi + AT Xf = Xi + ViT + 1/2AT^2 Vf^2 = Vi^2 + 2AXf BTW I don't need the answer to this exact problem. I just need to know how to do it on my test. Any help will be greatly appreciated.