Calculating Gravitational Attraction: Force of a 48.9 kg Student on Earth in N

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SUMMARY

The gravitational attraction between a student with a mass of 48.9 kg and Earth at the altitude of the space shuttle, where the gravitational field is 7.95 N/kg, can be calculated using the formula F = mg. Here, F represents the force in Newtons, m is the mass of the student, and g is the gravitational field strength. Substituting the values, the force of attraction is F = 48.9 kg * 7.95 N/kg, resulting in a force of approximately 388.55 N.

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Earth's gravitational field is 7.95 N/kg at the altitude of the space shuttle.
What is the size of the force of attraction between a student of mass 48.9 kg and Earth?

answer in units of N.

please help, i don't get how to do this!

thanks..
 
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7.95 N/kg = 7.95 m/s². This is the value of g at the shuttle, a bit smaller than it is at the surface of the Earth.

The force of gravity between two masses like the Earth and the student on the space shuttle is F = GMm/d² where M is the mass of the Earth and m the mass of the student. Often it is convenient to split this formula into two parts. We say F = mg and g = GM/d². It actually turns out that there really is a g field lying between the two masses. The M causes a gravitational field g around itself and the field causes the force on m. Anyway, that's all you need to do your problem!
 

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