Can Speed Be Negative?

  • Thread starter Thread starter Tabe
  • Start date Start date
  • Tags Tags
    Negative
Tabe
Messages
42
Reaction score
0
:confused: I know that you can have a negative acceleration, which would be considered deceleration, but is it possible to have a negative speed? It may sound like a stupid question to some people, but I am completely baffled.
 
Physics news on Phys.org
Don't worry :) I have that same misunderstanding when I started.

Velocity and Acceleration is a vector. That means it is a quantity WITH a direction. For example, I can assign the up direction as + and the down direction as -. Then when I drop an apple it will the acceleration = -g (negative), because it is going down. It is NOT possible to have a negative speed, but it is possible to have a negative VELOCITY.

Speed and Displacement is a vector - it is the quantity without direction.

Still don't understand? Try http://www.physicsclassroom.com/Class/1DKin/U1L1b.html
 
No we cannot have a negative speed...speed is not a vector quantity. It has only magnitude, not direction. Its value indicates the rate at which an object's distance traveled changes with time, but not in what direction.

Velocity, on the other hand, is a vector quantity. To describe an object's velocity, it is not sufficient to indicate only how fast it is going, but also in what direction.

For the special case of motion in a straight line, we can define a coordinate system such that the line along which the object is traveling is one of the coordinate axes that we have defined (say, the x-axis for example). Then, full blown vectors are not strictly required to describe the velocity...an algebraic scalar (a number with a sign) would be sufficient. If an object is traveling at 10 m/s on the x-axis, then what we call the scalar component of the velocity in the x-direction v_x is:

v_x = 10 m/s if it is traveling in the positive x-direction

v_x = -10 m/s if it is traveling in the negative x-direction

Since the object is traveling in a straight line, it obviously does not have components in any other direction (other than x!). So we can forget about the x and describe the object's velocity as v, a scalar that has an absolute value equal to the magnitude of the velocity vector, but unlike the magnitude, also has a sign that indicates the directional "sense" (+ or -) of the object's motion along the x-axis. We can write the velocity as

v = 10 m/s if it is traveling in the positive x-direction

v = -10 m/s if it is traveling in the negative x-direction

If you like, you can use the full blown vector notation instead:

\vec{v} = \text{(10 m/s)}\hat{i}

(travelling in positive x-direction)

OR

\vec{v} = -\text{(10 m/s)}\hat{i}

(travelling in negative x-direction).

One point of confusion to watch for (that only arises when the motion is confined along one axis and we choose to drop the x subscript). When using the scalar component notation, v indicates both magnitude (10m/s) and direction, which means it can be either positive or negative. In contrast, when using the vector notation, the same symbol "v" is actually the magnitude of the velocity vector:
v = |\vec{v}|
so it is always positive (magnitudes are always positive). The direction is instead given by the sign on the unit vector:
\pm \hat{i}.
 
Ok, thanks, that explains a lot. It also answers some of the other questions that I had about velocity.
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 19 ·
Replies
19
Views
1K
Replies
13
Views
5K
Replies
4
Views
2K
  • · Replies 16 ·
Replies
16
Views
6K
  • · Replies 1 ·
Replies
1
Views
882
  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 13 ·
Replies
13
Views
1K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 6 ·
Replies
6
Views
1K