Can the spin cause the collapse?

[forofo]

TL;DR

Solving 1D Dirac equation there are 2 matrixs, and from those we get the space probability and current. If that current reflects the spin state, could happen than the EM fields from the matter acting as potentials, drives the spin to up or down, and when it reaches the north os south pole in bloch sphere, there is the collapse.

Solving 1D Dirac equation there are 2 matrixs, and from those we get the space probability and current. If that current reflects the spin state, could happen than the EM fields from the matter acting as potentials, drives the spin to up or down, and when it reaches the north os south pole in bloch sphere, there is the collapse.
Not only Like the momentum is atached to the position (it's FFT), I also the current in Dirac equation is a view of it. So if the current matrix is driven to a state that reflects a spin in north or south pole in bloch sphere (like in grover's search ),then we could say that the particle has collapsed?. Also the I suposse that in that case the position matrix must have only one value.

 

[azntoon]

It is possible that the EM fields from matter acting as potentials can drive the spin to up or down, but there is no direct connection between this and the collapse of the wavefunction. The collapse of the wavefunction is usually associated with a measurement event, such as when the particle is observed by an observer. It is not clear how EM fields from matter acting as potentials would cause a collapse of the wavefunction. In regards to the Dirac equation, the current matrix does not necessarily reflect the spin state. The current matrix is related to the probability current, which describes how likely it is for a particle to move from one location to another. It does not necessarily reflect the spin state of the particle. Furthermore, it is not necessary for the position matrix to have only one value in order for the particle to collapse. The wavefunction of the particle will collapse once a measurement event occurs, regardless of the values in the position matrix.