Can Tidal Force Unlock Unlimited Energy Potential?

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appmathstudent
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Homework Statement
The origin of the Cartesian coordinates is at the Earth’s center. The moon is on the
z-axis, a fixed distance R away (center-to-center distance). The tidal force exerted by
the moon on a particle at the Earth’s surface (point x, y,z) is given by... **See picture on attempted solution**
Relevant Equations
Fx,Fy,Fz
Screenshot_20210330-170412_Chrome.jpg
 
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You are absolutely correct, that the potential is only determined up to an additive constant. Given any function ##\phi## such that ##\mathbf{F} = - \nabla \phi##, which in this case you may obtain by simply summing the negatives of the integrals of the components of the force [because of the separability, i.e. each force component only depends on its corresponding co-ordinate], ##\phi' = \phi + c## is also a valid solution.

In this case, the authors chose that the point of zero potential is ##\mathbf{x}_0 = (0,0,0)##.
 
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etotheipi said:
You are absolutely correct, that the potential is only determined up to an additive constant. Given any function ##\phi## such that ##\mathbf{F} = - \nabla \phi##, which in this case you may obtain by simply summing the negatives of the integrals of the components of the force [because here, each component only depends on its corresponding co-ordinate], ##\phi' = \phi + c## is also a valid solution.

In this case, the authors chose that the point of zero potential is ##\mathbf{x}_0 = (0,0,0)##.
Thank you very much for the explanation !