Can two different infinite series converge to the same limit?

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Discussion Overview

The discussion revolves around the question of whether two different convergent infinite series, \(\sum_{n=1}^{\infty}a_n\) and \(\sum_{n=1}^{\infty}b_n\), can converge to the same limit under certain conditions, specifically when \(a_n \leq b_n\) for all \(n\) and \(a_n < b_n\) for at least one \(n\). The inquiry also extends to scenarios where \(a_n < b_n\) for infinitely many \(n\).

Discussion Character

  • Debate/contested

Main Points Raised

  • One participant questions if two convergent series can have the same limit given that \(a_n \leq b_n\) for all \(n\) and \(a_n < b_n\) for at least one \(n\).
  • Another participant presents a mathematical argument suggesting that if \(a_i < b_i\) for some \(i\) and \(a_n \leq b_n\) for all \(n \neq i\), then the series \(\sum_{n \in \mathbb{N}}a_n\) must be strictly less than \(\sum_{n \in \mathbb{N}}b_n\).
  • One participant asserts that it is impossible for the two series to have the same limit, arguing that the presence of at least one term where \(a_n < b_n\) ensures that the partial sums of \(a_n\) will always be smaller than those of \(b_n\).

Areas of Agreement / Disagreement

Participants express differing views on whether the two series can converge to the same limit, with some arguing that they cannot while others present conditions under which they might. The discussion remains unresolved.

Contextual Notes

The discussion does not clarify the implications of the convergence of the series or the specific nature of the terms \(a_n\) and \(b_n\) beyond the stated inequalities.

raphile
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Hi,

The title of the thread doesn't adequately describe the question I want to ask, so here it is:

Suppose we have two infinite series, \sum_{n=1}^{\infty}a_n and \sum_{n=1}^{\infty}b_n, both of which are convergent. Also suppose a_n \leq b_n for all n, and a_n &lt; b_n for at least one n. Is it possible that they both converge to the same limit? Or can we say that \sum_{n=1}^{\infty}a_n is strictly smaller than \sum_{n=1}^{\infty}b_n?

If the answer to the above question is that they can have the same limit, then what if a_n&lt;b_n for infinitely many n?

Thanks!
 
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Suppose a_i &lt; b_i and that a_n \leq b_n for all n \neq i. Then if \sum_{n \in \mathbb{N}}a_n and \sum_{n \in \mathbb{N}}b_n converge, it is easy to show the following:
\sum_{n \leq i}a_n &lt; \sum_{n \leq i}b_n
\sum_{n &gt; i}a_n \leq \sum_{n &gt; i}b_n
Adding these together gives
\sum_{n \in \mathbb{N}}a_n = \sum_{n \leq i}a_n + \sum_{n &gt; i}a_n &lt; \sum_{n \leq i}b_n + \sum_{n &gt; i}b_n = \sum_{n \in \mathbb{N}}b_n
This should answer your question.
 
There is no way they can have the same limit. If you compare finite sums including at least one n where an < bn, then the a partial sum will be smaller and there is no way it can make up the difference without a term with a > b.
 
Ok, that's great, thanks!
 

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