Can u me with this questions ?

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SUMMARY

The discussion focuses on solving calculus problems, specifically finding the antiderivative of the function f(x) and its derivatives. The function provided is f(x) = 6x - e^(1-2x), with the first derivative calculated as f'(x) = 6 + 2e^(1-2x) and the second derivative as f''(x) = -4e^(1-2x). The equation f''(x) + 2f'(x) = 0 simplifies to 0 = 0, indicating a valid solution. The participants emphasize the importance of showing work for homework questions.

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Can u please help me with this questions ?

hi 4 all


and thz 4 all .
 

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for part 2a) you can take the antiderivative of f(x) from 1 to 4

2b)
f(x)=6x-e[tex]^{1-2x}[/tex]
f'(x)=6-e[tex]^{1-2x}[/tex](-2)
f'(x)=6+2e[tex]^{1-2x}[/tex]

f''(x)=2e[tex]^{1-2x}[/tex](-2)
f''(x)=-4e[tex]^{1-2x}[/tex]

f''(x)+2f'(x)=0
-4e[tex]^{1-2x}[/tex]+2[6+2e[tex]^{1-2x}[/tex]]-12=0
-4e[tex]^{1-2x}[/tex]+12+4e[tex]^{1-2x}[/tex]-12=0
0=0
OWNED!
 
If these are HW questions, then no- you have to show an attempt at the problems first.
 

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