Can You Calculate How Long it Takes to Drain a Car Battery with Headlights On?

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Homework Help Overview

The discussion revolves around calculating the time it takes to drain a car battery when the headlights and parking lights are left on. The problem involves understanding power consumption and battery capacity, specifically using a 60 Ah battery and the power ratings of the lights.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the total power consumed by the lights and the charge of the battery. There are attempts to relate power, current, and time using fundamental equations. Some participants question the need for the battery voltage to calculate current.

Discussion Status

The discussion is ongoing with participants exploring different aspects of the problem. Some have provided hints regarding assumptions about battery voltage, while others express frustration with the complexity of the problem and seek further clarification.

Contextual Notes

There is an implicit assumption about the voltage of the car battery, which is not explicitly stated in the original post. The original poster has expressed difficulty in progressing beyond initial calculations.

FredericChopin
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Homework Statement


The headlights on a car operate typically at 60 W and the parking lights typically at 5 W. Assuming that there are two main headlights and four parking lights, what length of time will it take to discharge a 60 Ah battery, if the lights are left on?

Homework Equations


I = Q/t

V = W/Q

P = W/t

P = I2*R

P = V2/R

P = IV

The Attempt at a Solution


I have gotten no where with this question. :frown:

All that I could do was find that the total power consumed by the lights:

PT = (2*10) + (4*5) = 140 W

, and the charge of the battery:

1 Ah = 3600 C
∴ 60 Ah = 216,000 C

, and that's it.

I have tried simultaneous equations by substitution and elimination but that doesn't work because all of the equations are derived from the base equations I = Q/t, V = W/Q and P = W/t, so I end up getting P = P all the time.

Hint's anybody?

Thank you.
 
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Not sure, but maybe you are suppose to assume that the voltage of the battery is the typical voltage for a car battery.
 
You need the voltage of the car battery to find the current. Look at Automotive battery - Wikipedia, the free encyclopedia, or just see the battery in your car...

ehild

FredericChopin said:

Homework Statement


The headlights on a car operate typically at 60 W and the parking lights typically at 5 W. Assuming that there are two main headlights and four parking lights, what length of time will it take to discharge a 60 Ah battery, if the lights are left on?


Homework Equations


I = Q/t

V = W/Q

P = W/t

P = I2*R

P = V2/R

P = IV

The Attempt at a Solution


I have gotten no where with this question. :frown:

All that I could do was find that the total power consumed by the lights:

PT = (2*10) + (4*5) = 140 W

, and the charge of the battery:

1 Ah = 3600 C
∴ 60 Ah = 216,000 C

, and that's it.

I have tried simultaneous equations by substitution and elimination but that doesn't work because all of the equations are derived from the base equations I = Q/t, V = W/Q and P = W/t, so I end up getting P = P all the time.

Hint's anybody?

Thank you.
 
Hmm... It seems like it... Based on this link, which is the worked solution to the question.

Thank you TSny and ehild.

So much for "complex, challenging and novel"... :rolleyes:
 

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