Can You Factorize This Complex Algebraic Expression?

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    2015
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SUMMARY

The complex algebraic expression $a(b^2+c^2-a^2 )+ b(c^2+a^2-b^2 )+ c(a^2+b^2-c^2 )-2abc$ has been successfully factorized by several members, including MarkFL, kaliprasad, greg1313, and Euge. The discussion centers around the Problem of the Week (POTW) format, which encourages collaborative problem-solving in algebra. Euge provided a detailed solution that adheres to the guidelines outlined in the forum.

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anemone
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Here is this week's POTW:

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Factorize $a(b^2+c^2-a^2 )+ b(c^2+a^2-b^2 )+ c(a^2+b^2-c^2 )-2abc$.

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Remember to read the http://www.mathhelpboards.com/showthread.php?772-Problem-of-the-Week-%28POTW%29-Procedure-and-Guidelines to find out how to http://www.mathhelpboards.com/forms.php?do=form&fid=2!
 
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Congratulations to the following members for their correct solution:

1. MarkFL
2. kaliprasad
3. greg1313
4. Euge

Solution from Euge:
We have
$$a(b^2 + c^2 - a^2) + b(c^2 + a^2 - b^2) + c(a^2 + b^2 - c^2) - 2abc$$
$$=[a(b^2 + c^2 - a^2) + 2abc] + [b(c^2 + a^2 - b^2) - 2abc] + [c(a^2 + b^2 - c^2) - 2abc]$$
$$= a[(b + c)^2 - a^2] + b[(c - a)^2 - b^2] + c[(a - b)^2 - c^2]$$
$$= a(b + c - a)(b + c + a) + b(c - a - b)(c - a + b) - c(c + b - a)(a - b + c)$$
$$= (b + c - a)[a(b + c + a) + b(c - a - b) - c(a - b + c)]$$
$$= (b + c - a)[a^2 - (b^2 - 2bc + c^2)]$$
$$= (b + c - a)[a^2 - (b - c)^2]$$
$$= (b + c - a)(a - b + c)(a + b - c).$$
 

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