MHB Can You Factorize This Complex Algebraic Expression?

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    2015
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The discussion focuses on the problem of factorizing the algebraic expression a(b^2+c^2-a^2 )+ b(c^2+a^2-b^2 )+ c(a^2+b^2-c^2 )-2abc. Several members successfully provided correct solutions, with notable contributions from MarkFL, kaliprasad, greg1313, and Euge. Euge's solution is highlighted as a key response in the thread. The problem is part of the weekly Problem of the Week (POTW) initiative, encouraging mathematical engagement among members. The thread emphasizes the importance of following guidelines for participation and solution submission.
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Here is this week's POTW:

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Factorize $a(b^2+c^2-a^2 )+ b(c^2+a^2-b^2 )+ c(a^2+b^2-c^2 )-2abc$.

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Remember to read the http://www.mathhelpboards.com/showthread.php?772-Problem-of-the-Week-%28POTW%29-Procedure-and-Guidelines to find out how to http://www.mathhelpboards.com/forms.php?do=form&fid=2!
 
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Congratulations to the following members for their correct solution:

1. MarkFL
2. kaliprasad
3. greg1313
4. Euge

Solution from Euge:
We have
$$a(b^2 + c^2 - a^2) + b(c^2 + a^2 - b^2) + c(a^2 + b^2 - c^2) - 2abc$$
$$=[a(b^2 + c^2 - a^2) + 2abc] + [b(c^2 + a^2 - b^2) - 2abc] + [c(a^2 + b^2 - c^2) - 2abc]$$
$$= a[(b + c)^2 - a^2] + b[(c - a)^2 - b^2] + c[(a - b)^2 - c^2]$$
$$= a(b + c - a)(b + c + a) + b(c - a - b)(c - a + b) - c(c + b - a)(a - b + c)$$
$$= (b + c - a)[a(b + c + a) + b(c - a - b) - c(a - b + c)]$$
$$= (b + c - a)[a^2 - (b^2 - 2bc + c^2)]$$
$$= (b + c - a)[a^2 - (b - c)^2]$$
$$= (b + c - a)(a - b + c)(a + b - c).$$
 
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