Can you guys check these calculations for me

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SUMMARY

The forum discussion centers on the calculations related to the kinetic energy of a .50 Caliber round fired from a Barrett M82 rifle and its potential effect on a blob of tissue. The kinetic energy (KE) of a single round is calculated as 16.98 kJ, leading to a total energy of approximately 170 kJ for 10 rounds. The discussion also highlights the specific heat capacities of normal human tissue and adipose tissue, which are essential for determining the temperature increase of the blob. The calculations reveal that the temperature increase of the blob is approximately 0.016 degrees Celsius.

PREREQUISITES
  • Understanding of kinetic energy calculations (KE = ½mv²)
  • Knowledge of specific heat capacity concepts
  • Familiarity with mass and weight conversions (e.g., pounds to kilograms)
  • Basic principles of thermodynamics related to temperature change
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  • Research the effects of kinetic energy on biological tissues
  • Explore advanced thermodynamics principles related to heat transfer
  • Learn about the properties of different types of tissues in human anatomy
  • Investigate the implications of ballistic impacts on soft tissue
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This discussion is beneficial for physicists, biomedical engineers, forensic scientists, and anyone interested in the effects of ballistic impacts on biological tissues.

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Background Information:
Clip Capacity of a Barret M82: 10 Rounds
Mass of a .50 Cal Round: 46.7 grams = .0467 Kg
Source: small arms by martin j. dougherty
Average Muzzle Velocity of a Barret M82 .50 Cal Rifle: 853 m/s
Average Specific heat capacity of normal human tissue: 3470 J/kg.C
http://www.engineeringtoolbox.com/human-body-specific-heat-d_393.html
Average Specific heat capacity of Adipose tissue: 2348J/kg.C
Source: http://www.itis.ethz.ch/itis-for-health/tissue-properties/database/heat-capacity/
Weight of Blob: 976 lbs = 442.7 Kg

Assumptions: Blob is around 75% adipose tissue(by weight) the remaining being normal body tissue. This means 332 Kg is adipose tissue. 110.6 Kg is other misc. body tissue.
Important Formula:
Kinetic Energy: Pe= ½mv2

Calculations:

Ke= 1/2 (.0467 Kg)(853 m/s)2 = 16.98 Kj = 16980 J

Joules needed to Raise blob 1 Degrees celsius:
(332 Kg * 2348 J/Kg) + (2348J/Kg * 110.6 Kg)= 779536J + 259688J= 1039224 J = 1039 Kj
How much does Blob’s Temperature increase? : 19.98/ 1039 = .016 degrees celsius
 
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Pe= ½mv2

That should be "KE" not PE but otherwise looks ok.

I made the KE of each round..

= 0.5 * .0467 * 8532 = 16.9 kJ not 19.98 kJ

There are 10 rounds so the energy is about 170 kJ.
 

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